动态规划最大利润的问题

# 求解最优性的问题
# 线性动规
# 区域动归


a = [1, 3, 4, 5, 6, 2, 7]


def foo(arr):
    if len(arr) <= 1:
        return 0
    min_num = arr[0]
    max_num = 0

    for item in arr:
        history = item - min_num  # 历史利润最大的
        max_num = max(max_num, history)
        min_num = min(min_num, item)
    return max_num, min_num


if __name__ == '__main__':
    print(foo(a))

  

原文地址:https://www.cnblogs.com/c-x-a/p/11065721.html