洛谷P3386 【模板】二分图匹配

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板子,直接用dinic

 1 //minamoto
 2 #include<iostream>
 3 #include<cstdio>
 4 #include<cstring>
 5 #include<queue>
 6 #define inf 0x3f3f3f3f
 7 using namespace std;
 8 #define getc() (p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<21,stdin),p1==p2)?EOF:*p1++)
 9 char buf[1<<21],*p1=buf,*p2=buf;
10 inline int read(){
11     #define num ch-'0'
12     char ch;bool flag=0;int res;
13     while(!isdigit(ch=getc()))
14     (ch=='-')&&(flag=true);
15     for(res=num;isdigit(ch=getc());res=res*10+num);
16     (flag)&&(res=-res);
17     #undef num
18     return res;
19 }
20 const int N=2005,M=2100005;
21 int ver[M],Next[M],head[N],edge[M],tot=1;
22 int dep[N],cur[N],s,t;
23 int n,m,k;
24 queue<int> q;
25 inline void add(int u,int v,int e){
26     ver[++tot]=v,Next[tot]=head[u],head[u]=tot,edge[tot]=e;
27     ver[++tot]=u,Next[tot]=head[v],head[v]=tot,edge[tot]=0;
28 }
29 bool bfs(){
30     memset(dep,-1,sizeof(dep));
31     while(!q.empty()) q.pop();
32     for(int i=s;i<=t;++i) cur[i]=head[i];
33     q.push(s),dep[s]=0;
34     while(!q.empty()){
35         int u=q.front();q.pop();
36         for(int i=head[u];i;i=Next[i]){
37             int v=ver[i];
38             if(dep[v]<0&&edge[i]){
39                 dep[v]=dep[u]+1,q.push(v);
40                 if(v==t) return true;
41             }
42         }
43     }
44     return false;
45 }
46 int dfs(int u,int limit){
47     if(!limit||u==t) return limit;
48     int flow=0,f;
49     for(int i=cur[u];i;i=Next[i]){
50         int v=ver[i];cur[u]=i;
51         if(dep[v]==dep[u]+1&&(f=dfs(v,min(limit,edge[i])))){
52             flow+=f,limit-=f;
53             edge[i]-=f,edge[i^1]+=f;
54             if(!limit) break;
55         }
56     }
57     return flow;
58 }
59 int dinic(){
60     int flow=0;
61     while(bfs()) flow+=dfs(s,inf);
62     return flow;
63 }
64 int main(){
65     n=read(),m=read(),k=read();
66     s=0,t=n+m+1;
67     for(int i=1;i<=n;++i) add(s,i,1);
68     for(int i=n+1;i<=n+m;++i) add(i,t,1);
69     for(int i=1;i<=k;++i){
70         int u=read(),v=read();
71         if(v>m) continue;
72         add(u,v+n,1);
73     }
74     printf("%d
",dinic());
75     return 0;
76 }
原文地址:https://www.cnblogs.com/bztMinamoto/p/9509694.html