gcd-模板+最小公倍数

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<algorithm>
 4 using namespace std;
 5 int GCD(int a,int b)
 6 {
 7     for(;a>0&&b>0;a>b?a%=b:b%=a);
 8     return a+b;//最大公约数;
 9 }
10 int main()
11 {
12     int a,b;
13     while(cin>>a>>b)
14     {
15         int ans=GCD(a,b);
16         cout<<ans<<endl;
17         cout<<a*b/ans<<endl;//最小公倍数;
18     }
19     return 0;
20 }
View Code
1     ll gcd (ll a, ll b) 
2 {
3     return ( a ? gcd(b%a, a) : b );
4 }
原文地址:https://www.cnblogs.com/by-1075324834/p/4514648.html