【HDOJ】3727 Jewel

静态区间第K大值。主席树和划分树都可解。

  1 /* 3727 */
  2 #include <iostream>
  3 #include <sstream>
  4 #include <string>
  5 #include <map>
  6 #include <queue>
  7 #include <set>
  8 #include <stack>
  9 #include <vector>
 10 #include <deque>
 11 #include <algorithm>
 12 #include <cstdio>
 13 #include <cmath>
 14 #include <ctime>
 15 #include <cstring>
 16 #include <climits>
 17 #include <cctype>
 18 #include <cassert>
 19 #include <functional>
 20 #include <iterator>
 21 #include <iomanip>
 22 using namespace std;
 23 //#pragma comment(linker,"/STACK:102400000,1024000")
 24 
 25 #define sti                set<int>
 26 #define stpii            set<pair<int, int> >
 27 #define mpii            map<int,int>
 28 #define vi                vector<int>
 29 #define pii                pair<int,int>
 30 #define vpii            vector<pair<int,int> >
 31 #define rep(i, a, n)     for (int i=a;i<n;++i)
 32 #define per(i, a, n)     for (int i=n-1;i>=a;--i)
 33 #define clr                clear
 34 #define pb                 push_back
 35 #define mp                 make_pair
 36 #define fir                first
 37 #define sec                second
 38 #define all(x)             (x).begin(),(x).end()
 39 #define SZ(x)             ((int)(x).size())
 40 // #define lson            l, mid, rt<<1
 41 // #define rson            mid+1, r, rt<<1|1
 42 
 43 typedef struct {
 44     int q;
 45     int l, r, k;
 46 } Ques_t;
 47 
 48 const int maxq = 210000;
 49 const int maxn = 1e5+5;
 50 const int maxm = maxn * 20;
 51 int a[maxn], m;
 52 Ques_t Q[maxq];
 53 int T[maxn];
 54 int lson[maxm], rson[maxm], c[maxm];
 55 int tot, cur, q;
 56 
 57 void init() {
 58     tot = cur = m = 0;
 59 }
 60 
 61 int Build(int l, int r) {
 62     int rt = tot++;
 63     
 64     c[rt] = 0;
 65     if (l == r)
 66         return rt;
 67     
 68     int mid = (l + r) >> 1;
 69     
 70     lson[rt] = Build(l, mid);
 71     rson[rt] = Build(mid+1, r);
 72     
 73     return rt;
 74 }
 75 
 76 int Insert(int rt, int x, int delta) {
 77     int nrt = tot++, ret = nrt;
 78     int l = 0, r = m - 1, mid;
 79     
 80     c[nrt] = c[rt] + delta;
 81     while (l < r) {
 82         mid = (l + r) >> 1;
 83         if (x <= mid) {
 84             lson[nrt] = tot++;
 85             rson[nrt] = rson[rt];
 86             nrt = lson[nrt];
 87             rt = lson[rt];
 88             r = mid;
 89         } else {
 90             lson[nrt] = lson[rt];
 91             rson[nrt] = tot++;
 92             nrt = rson[nrt];
 93             rt = rson[rt];
 94             l = mid + 1;
 95         }
 96         c[nrt] = c[rt] + delta;
 97     }
 98     
 99     return ret;
100 }
101 
102 int Query_kth(int lrt, int rrt, int k) {
103     int l = 0, r = m - 1, mid;
104     int tmp;
105     
106     while (l < r) {
107         mid = (l + r) >> 1;
108         tmp = c[lson[rrt]] - c[lson[lrt]];
109         if (tmp >= k) {
110             lrt = lson[lrt];
111             rrt = lson[rrt];
112             r = mid;
113         } else {
114             k -= tmp;
115             lrt = rson[lrt];
116             rrt = rson[rrt];
117             l = mid + 1;
118         }
119     }
120     
121     return l;
122 }
123 
124 int Query_Rank(int rt, int L, int R, int l, int r) {
125     if (L==l && R==r)
126         return c[rt];
127     
128     int mid = (l + r) >> 1;
129     
130     if (R <= mid)
131         return Query_Rank(lson[rt], L, R, l, mid);
132     else if (L > mid)
133         return Query_Rank(rson[rt], L, R, mid+1, r);
134     else
135         return Query_Rank(lson[rt], L, mid, l, mid) + Query_Rank(rson[rt], mid+1, R, mid+1, r); 
136 }
137 
138 void solve() {
139     __int64 ans1 = 0, ans2 = 0, ans3 = 0;
140     int tmp, id;
141     
142     sort(a, a+m);
143     m = unique(a, a+m) - a;
144     T[cur] = Build(0, m-1);
145     
146     rep(i, 0, q) {
147         if (Q[i].q == 0) {
148             id = lower_bound(a, a+m, Q[i].k) - a;
149             T[cur+1] = Insert(T[cur], id, 1);
150             ++cur;
151             continue;
152         }
153         
154         if (Q[i].q == 1) {
155             id = Query_kth(T[Q[i].l-1], T[Q[i].r], Q[i].k);
156             tmp = a[id];
157             ans1 += tmp;
158         } else if (Q[i].q == 2) {
159             id = lower_bound(a, a+m, Q[i].k) - a;
160             tmp = Query_Rank(T[cur], 0, id, 0, m-1);
161             ans2 += tmp;
162         } else {
163             id = Query_kth(T[0], T[cur], Q[i].k);
164             tmp = a[id];
165             ans3 += tmp;
166         }
167         
168         #ifndef ONLINE_JUDGE
169             // printf("tmp = %d
", tmp);
170         #endif
171     }
172     
173     printf("%I64d
%I64d
%I64d
", ans1, ans2, ans3);
174 }
175 
176 int main() {
177     ios::sync_with_stdio(false);
178     #ifndef ONLINE_JUDGE
179         freopen("data.in", "r", stdin);
180         freopen("data.out", "w", stdout);
181     #endif
182     
183     int t = 0;
184     char op[16];
185     
186     while (scanf("%d", &q)!=EOF) {
187         init();
188         rep(i, 0, q) {
189             scanf("%s", op);
190             if (op[0] == 'I') {
191                 scanf("%d", &Q[i].k);
192                 a[m++] = Q[i].k;
193                 Q[i].q = 0;
194             } else if (op[6] == '1') {
195                 scanf("%d %d %d", &Q[i].l, &Q[i].r, &Q[i].k);
196                 Q[i].q = 1;
197             } else if (op[6] == '2') {
198                 scanf("%d", &Q[i].k);
199                 Q[i].q = 2;
200             } else {
201                 scanf("%d", &Q[i].k);
202                 Q[i].q = 3;
203             }
204         }
205         printf("Case %d:
", ++t);
206         solve();
207     }
208     
209     #ifndef ONLINE_JUDGE
210         printf("time = %d.
", (int)clock());
211     #endif
212     
213     return 0;
214 }

数据发生器。

 1 from copy import deepcopy
 2 from random import randint, shuffle
 3 import shutil
 4 import string
 5 
 6 
 7 def GenDataIn():
 8     with open("data.in", "w") as fout:
 9         t = 10
10         bound = 10**5
11         for tt in xrange(t):
12             n = randint(200, 300)
13             fout.write("%d
" % (n))
14             L = range(1, n+1)
15             shuffle(L)
16             cur = 0
17             has = []
18             for i in xrange(n):
19                 op = randint(0, 3)
20                 if cur==0:
21                     op=0
22                 if op==0:
23                     idx = randint(0, len(L)-1)
24                     x = L[idx]
25                     L.remove(x)
26                     has.append(x)
27                     cur += 1
28                     fout.write("Insert %d
" % x)
29                 elif op==1:
30                     l = randint(1, cur)
31                     r = randint(l, cur)
32                     k = randint(1, r-l+1)
33                     fout.write("Query_1 %d %d %d
" % (l, r, k))
34                 elif op==2:
35                     idx = randint(0, len(has)-1)
36                     x = has[idx]
37                     fout.write("Query_2 %d
" % x)
38                 else:
39                     x = randint(1, cur)
40                     fout.write("Query_3 %d
" % x)
41             
42                 
43 def MovDataIn():
44     desFileName = "F:eclipse_prjworkspacehdojdata.in"
45     shutil.copyfile("data.in", desFileName)
46 
47     
48 if __name__ == "__main__":
49     GenDataIn()
50     MovDataIn()
原文地址:https://www.cnblogs.com/bombe1013/p/5189818.html