转 group_concat函数详解

MySQL中group_concat函数


完整的语法如下:


group_concat([DISTINCT] 要连接的字段 [Order BY ASC/DESC 排序字段] [Separator '分隔符'])

基本查询

Sql代码  收藏代码
  1. select * from aa;  


+------+------+
| id| name |
+------+------+
|1 | 10|
|1 | 20|
|1 | 20|
|2 | 20|
|3 | 200 |
|3 | 500 |
+------+------+
6 rows in set (0.00 sec)

以id分组,把name字段的值打印在一行,逗号分隔(默认)

Sql代码  收藏代码
  1. select id,group_concat(name) from aa group by id;  


+------+--------------------+
| id| group_concat(name) |
+------+--------------------+
|1 | 10,20,20|
|2 | 20 |
|3 | 200,500|
+------+--------------------+
3 rows in set (0.00 sec)

以id分组,把name字段的值打印在一行,分号分隔

Java代码  收藏代码
  1. select id,group_concat(name separator ';') from aa group by id;  


+------+----------------------------------+
| id| group_concat(name separator ';') |
+------+----------------------------------+
|1 | 10;20;20 |
|2 | 20|
|3 | 200;500 |
+------+----------------------------------+
3 rows in set (0.00 sec)

以id分组,把去冗余的name字段的值打印在一行,


逗号分隔

Sql代码  收藏代码
  1. select id,group_concat(distinct name) from aa group by id;  


+------+-----------------------------+
| id| group_concat(distinct name) |
+------+-----------------------------+
|1 | 10,20|
|2 | 20 |
|3 | 200,500 |
+------+-----------------------------+
3 rows in set (0.00 sec)

以id分组,把name字段的值打印在一行,逗号分隔,以name排倒序

Sql代码  收藏代码
  1. select id,group_concat(name order by name desc) from aa group by id;  


+------+---------------------------------------+
| id| group_concat(name order by name desc) |
+------+---------------------------------------+
|1 | 20,20,10 |
|2 | 20|
|3 | 500,200|
+------+---------------------------------------+
3 rows in set (0.00 sec)

测试sql,项目中用到的。

Sql代码 
SELECT  
        EMPLOYEES.EMPID  
        ,EMPLOYEES.EMPNAME  
        ,DEPARTMENTS.DEPARTMENTNAME  
        ,EMPLOYEES.DEPTID  
        ,EMPLOYEES.EMPPWD  
        ,EMPLOYEES.INSIDEEMAIL  
        ,EMPLOYEES.OUTSIDEEMAIL  
        ,EMPLOYEES.DELEFLAG  
        ,EMPLOYEES.EMPCLASS  
        ,(CONCAT('[', <span style="color: #ff0000;">GROUP_CONCAT</span>  
(ROLE.Role_Name SEPARATOR '],['), ']')) AS ROLENAME  
        ,(concat( '[', (  
            SELECT  
                    <span style="color: #ff0000;">GROUP_CONCAT</span>  
(DEPARTMENTS.DEPARTMENTNAME separator '],[')  
                FROM  
                    EMP_ROLE_DEPT  
                        LEFT JOIN DEPARTMENTS  
                            ON (  
                                DEPARTMENTS.DEPARTMENTID = EMP_ROLE_DEPT.DEPTID  
                                AND DEPARTMENTS.DELEFLAG = 0  
                            )  
                GROUP BY  
                    EMP_ROLE_DEPT.EMPID  
                HAVING  
                    EMP_ROLE_DEPT.EMPID = EMPLOYEES.EMPID  
        ),']')) AS DEPARTMENTRIGHT  
    FROM  
        EMPLOYEES  
            LEFT JOIN DEPARTMENTS  
                ON (  
                    DEPARTMENTS.DEPARTMENTID = EMPLOYEES.DEPTID  
                    AND DEPARTMENTS.DELEFLAG = 0  
                )  
            LEFT JOIN ROLE_EMP  
                ON (ROLE_EMP.EMP_ID = EMPLOYEES.EMPID)  
            LEFT JOIN ROLE  
                ON (ROLE_EMP.ROLE_ID = ROLE.ROLE_ID)  
<span style="color: #ff0000;">    GROUP BY  
        EMPLOYEES.EMPID</span>  
  
    HAVING  
        EMPLOYEES.EMPID LIKE '%%'  
        AND EMPLOYEES.EMPNAME LIKE '%%'  
        AND EMPLOYEES.DELEFLAG = 0  
        AND (  
            EMPLOYEES.EMPCLASS = '1'  
            OR EMPLOYEES.EMPCLASS = '2'  
        )  
        AND EMPLOYEES.DEPTID = '001' LIMIT 0  
        ,16   
原文地址:https://www.cnblogs.com/bluedeblog/p/7446297.html