习题2

#include<stdio.h>
int main(void)
{
    double n,y;

    printf("Enter n:");
    scanf_s("%lf",&n);

    if(n<=50){
        y=n*0.53;
    }
    else if(n>50){
        y=n*0.58;
    }
    printf("f(%.2f)=%.2f
",n,y);

    return 0;
}

原文地址:https://www.cnblogs.com/blgl/p/3370555.html