例3-11

#include<stdio.h>
int main(void)
{
    double valuel,value2;
    char op;

    printf("Type in an expression:");
    scanf_s("%lf%c%lf",&valuel,&op,&value2);
    if(op=='+')
        printf("%.2f
",valuel+value2);
    else if(op=='-')
        printf("%.2f
",valuel-value2);
    else if(op=='*')
        printf("%.2f
",valuel*value2);
    else if(op=='/')
        if(value2!=0)
        printf("%.2f
",valuel/value2);
    else
        printf("Divisor can not be 0!
");
    else
        printf("Unkown operator!
");

    return 0;
}

原文地址:https://www.cnblogs.com/blgl/p/3354501.html