硬币的问题

不同的表面值Value[ ]有硬币的数量Num[ ]限制，凑齐Goal表面值,的需求的最小和最大数目。
static int  Min = 1<<10;
static  int Max = 0;
static int* set;
static int* Count;


void LeastCoin_N(int* Value, int* Num, int Len, int Goal, int cur) 
{   
	if(Goal == 0) 
	{
		if(cur > Max)
		{
			for(int i = 0; i < Len; i++)
			{		
				for(int j = 0; j < cur; j++)
				{
					if(Value[i] == set[j])
					{
						Count[i]++;
						if(Count[i] > Num[i])
						{
							goto  initial;
						}
					}

				}
			}

			for(int i = 0; i < cur; i++)
			{
			     printf("%d ", set[i]);  
			}
			Max = cur;
		}
		if(Min > cur)
		{			
			for(int i = 0; i < Len; i++)
			{		
				for(int j = 0; j < cur; j++)
				{
					if(Value[i] == set[j])
					{
						Count[i]++;
						if(Count[i] > Num[i])
						{
							goto  initial;
						}
					}

				}
			}  
		
			for(int i = 0; i < cur; i++)
			{
				printf("%d ", set[i]); 
			}
			        Min = cur;
		}
initial:	
		memset(Count, 0 , sizeof(int)*Len);
		printf("
");
	}
	else
	{
		for(int i = 0; i < Len; i++)
		{

			if(Goal >= Value[i]) 
			{
				
			        int ok = 1;
				for(int j = 0; j < cur; j++)
				{
					if(set[j] > Value[i])
					{
						ok = 0;
						break;
					}
					
				}
				if(ok)
				{				
					set[cur] = Value[i];  
					LeastCoin_N(Value, Num, Len, Goal - Value[i], cur + 1);				
				}
			}		

		}

	}
 
}

int WLeastCoin_N(int* Value, int* Num, int Len,int Goal)
{

	printf("goal: %d
", Goal);

	set = new int [Len];
	memset(set, 0 , sizeof(int)*Len);
	Count = new int [Len];
	memset(Count, 0 , sizeof(int)*Len);

	int cur = 0;
	LeastCoin_N(Value, Num, Len, Goal,  cur);
	printf("Max:%d 
", Max);
	printf("Min:%d 
", Min);
	return 0;

}