#二：周末综合作业：
# 2.1：编写用户登录接口
#1、输入账号密码完成验证，验证通过后输出"登录成功"
#2、可以登录不同的用户
#3、同一账号输错三次锁定，（提示：锁定的用户存入文件中，这样才能保证程序关闭后，该用户仍然被锁定）
tag = True
dict = {}
while tag:
inp_name = input('输入账号：')
with open(r'b.txt', mode='r', encoding='utf-8') as f1:
if inp_name in f1:
print('该账户已被锁定')
tag = False
break
inp_paw = input('输入密码：')
with open(r'a.txt', mode='rt', encoding='utf-8') as f:
for line in f:
name,pwd = line.strip().split(':')
if name == inp_name and pwd == inp_paw:
print('登入成功')
tag = False
break
elif name == inp_name and pwd != inp_paw:
print('密码错误')
if name not in dict:
dict[name]=0
dict[name] = dict.get(name)+1
if dict[name] == 3:
with open(r'b.txt', mode='a', encoding='utf-8') as f1:
f1.write(name)
print('该用户被锁定')
tag = False
break
else:
print('账号不存在')
# 2.2：编写程序实现用户注册后，可以登录，
dict = {}
while True:
msg = """
0 退出
1 登录
2 注册
"""
print(msg)
cmd = input('请输入命令编号>>: ').strip()
if not cmd.isdigit():
print('必须输入命令编号的数字，傻叉')
continue
if cmd == '0':
break
elif cmd == '1':
inp_name = input('输入账号：')
with open(r'b.txt', mode='r', encoding='utf-8') as f1:
if inp_name in f1:
print('该账户已被锁定')
break
inp_paw = input('输入密码：')
with open(r'a.txt', mode='rt', encoding='utf-8') as f:
for line in f:
name,pwd = line.strip().split(':')
if name == inp_name and pwd == inp_paw:
print('登入成功')
break
elif name == inp_name and pwd != inp_paw:
print('密码错误')
if name not in dict:
dict[name]=0
dict[name] = dict.get(name)+1
if dict[name] == 3:
with open(r'b.txt', mode='a', encoding='utf-8') as f1:
f1.write(name)
print('该用户被锁定')
break
else:
print('账号不存在')
elif cmd == '2':
inp_name = input('输入账号：')
inp_paw = input('输入密码：')
with open(r'a.txt', mode='rt',encoding='utf-8') as f:
for line in f:
name, pwd = line.strip().split(':')
if name == inp_name:
print('账号已存在')
break
else:
with open(r'a.txt', mode='at', encoding='utf-8') as f:
f.write('{}:{}
'.format(inp_name,inp_paw))
print('注册成功')
else:
print('输入的命令不存在')
# 思考：上述这个if分支的功能否使用其他更为优美地方式实现
#二：周末综合作业：
# 2.1：编写用户登录接口
#1、输入账号密码完成验证，验证通过后输出"登录成功"
#2、可以登录不同的用户
#3、同一账号输错三次锁定，（提示：锁定的用户存入文件中，这样才能保证程序关闭后，该用户仍然被锁定）
tag = True
while tag:
# 1) 接收用户输入的账号
username = input('请输入账号: ').strip()
# 2) 从user_info3.txt文件中读取用户的数据进行校验
with open('user_info3.txt', 'r', encoding='utf-8') as f,
open('user_info_copy.txt', 'w', encoding='utf-8') as w: # w模式
# 将user_info3.txt文件中的每一行数据读取出来，然后赋值给user_pwd
for user_pwd in f:
# user_info3.txt中有换行符的情况下
# 先将换行符去掉，然后再根据:号进行切割
user, pwd, count = user_pwd.strip().split(':')
# print(f'文件中存放的账号与密码是: {user} {pwd}')
count = int(count)
# 3) 先校验用户名
if username == user: # 若账号存在则成立，否则不成立
# print(username)
# 4) 若用户名存在，初始让用户输入三次机会，继续输入密码
while count < 3: # 初始 0<3
password = input('请输入密码: ').strip()
if password == pwd:
# 登录成功后，结束所有循环
print('登录成功!')
tag = False
break
else:
print('登录失败!')
count += 1
# 若当前用户的计数为3，代表已被锁定
if count == 3: # 当用户计数为3时，打印锁定
print('当前用户以被锁定')
# 5) 在此处将，未修改与修改后的用户数据写入user_info_copy.txt文件中
w.write(f'{user}:{pwd}:{count}
')
# 6) 删除user_info3.txt文件
import os
os.remove('user_info3.txt')
# 7) 将user_info_copy.txt改名为user_info3.txt文件
os.rename('user_info_copy.txt', 'user_info3.txt')
# 作业: 通过文件处理时限 6、7步骤
dic = {
'0': '退出',
'1': '登录',
'2': '注册',
}
tag = True
while tag:
msg = """
0 退出
1 登录
2 注册
"""
print(msg)
cmd = input('请输入命令编号>>: ').strip()
if not cmd.isdigit():
print('必须输入命令编号的数字，傻叉')
continue
if cmd not in dic:
print('输入有误')
continue
print(dic.get(cmd))
if cmd == '0':
break
elif cmd == '1':
while tag:
username = input('请输入用户名: ').strip()
password = input('请输入密码: ').strip()
with open('a.txt', 'r', encoding='utf-8') as f:
for line in f:
user, pwd = line.strip().split(':')
if username == user and password == pwd:
print('登录成功!')
tag = False
break
elif username == user and password != pwd:
print('密码错误')
break
else:
print('无此用户')
elif cmd == '2':
while tag :
inp_name = input('输入账号：')
with open(r'a.txt', mode='rt',encoding='utf-8') as f,open(r'a.txt', mode='at', encoding='utf-8') as w:
for line in f:
name, pwd = line.strip().split(':')
if name == inp_name:
print('账号已存在')
break
else:
inp_paw = input('输入密码：')
w.write('{}:{}
'.format(inp_name,inp_paw))
print('注册成功')
tag = False