LeetCode Minimum Path Sum

Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

Note: You can only move either down or right at any point in time.

 1 public class Solution {
 2     public int minPathSum(int[][] grid) {
 3             if (grid==null) {
 4                 return 0;
 5             }
 6             int minpath=0;
 7             int m=grid.length;
 8             int n=grid[0].length;
 9             int[][] sumpath=new int[m][n];
10             sumpath[0][0]=grid[0][0];
11         for (int j = 1; j < n; j++) {
12             sumpath[0][j]=sumpath[0][j-1]+grid[0][j];
13         }
14         
15         for (int i = 1; i < m; i++) {
16             sumpath[i][0]=sumpath[i-1][0]+grid[i][0];
17         }
18         
19         for (int i = 1; i < m; i++) {
20             for (int j = 1; j < n; j++) {
21                 sumpath[i][j]=grid[i][j]+Math.min(sumpath[i][j-1], sumpath[i-1][j]);
22             }
23         }
24         
25         return sumpath[m-1][n-1];
26     }
27 }
原文地址:https://www.cnblogs.com/birdhack/p/4033522.html