C#调用Lame.exe

string lameEXE = @"D:lame3.100lame.exe";
            string lameArgs = "-b 128";

            string wavFile = @"d:d.mp3";
            string mp3File = @"d:ff.mp3";

            Process process = new Process();
            process.StartInfo = new ProcessStartInfo();
            process.StartInfo.FileName = lameEXE;
            process.StartInfo.Arguments = string.Format(
                "{0} {1} {2}",
                lameArgs,
                wavFile,
                mp3File);

            process.Start();
            process.WaitForExit();

            int exitCode = process.ExitCode;
            Console.WriteLine(exitCode);
原文地址:https://www.cnblogs.com/binlyzhuo/p/9394593.html