hdu_5961_传递(bitset)

题目链接:hdu_5961_传递

题意:

中文,不解释

题解:

上bitset卡常,很优美的就过去了

 1 #include<bits/stdc++.h>
 2 #define F(i,a,b) for(int i=a;i<=b;i++)
 3 using namespace std;
 4 typedef long long ll;
 5 
 6 bitset<2020>Q[2020],P[2020],*pp,now;
 7 
 8 int t,n;
 9 char G[2020][2020];
10 
11 int check(bitset<2020>*pp)
12 {
13     F(i,1,n)F(j,1,n)
14     {
15         if(pp[i][j])
16         {
17             now=((~pp[i])&pp[j]);
18             if(now.any())return 1;
19         }
20     }
21     return 0;
22 }
23 
24 int main()
25 {
26     scanf("%d",&t);
27     while(t--)
28     {
29         scanf("%d",&n);
30         F(i,1,n)Q[i].reset(),P[i].reset();
31         F(i,1,n)scanf("%s",&G[i][1]);
32         F(i,1,n)F(j,1,n)
33         {
34             if(G[i][j]=='P')P[i][j]=1;
35             if(G[i][j]=='Q')Q[i][j]=1;
36         }
37         if(check(P))puts("N");
38         else if(check(Q))puts("N");
39         else puts("T");
40         
41     }
42     return 0;
43 }
View Code
原文地址:https://www.cnblogs.com/bin-gege/p/6033866.html