计算几何复习笔记

求两个直线交点

inline point jiaodian(line x,line y)
{
    point hu=x.x-y.x;
    double gu=(y.y*hu)/(x.y*y.y);
    return x.x+(x.y*gu);
}
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原文地址:https://www.cnblogs.com/betablewaloot/p/12411932.html