题目描述
给一个链表,若其中包含环,请找出该链表的环的入口结点,否则,输出null。
python solution:
# -*- coding:utf-8 -*-
class ListNode:
def __init__(self, x):
self.val = x
self.next = None
class Solution:
def EntryNodeOfLoop(self, pHead):
if not pHead or not pHead.next:
return None
fast,slow = pHead,pHead
#判断是否有环
l = 1
while fast.next.next:
fast = fast.next.next
slow = slow.next
if fast==slow: #判断环有多长
# print(fast.val,slow.val)
fast = fast.next
while fast!=slow:
fast = fast.next
l += 1
# print(l)
#寻找入口结点
fast,slow = pHead,pHead
while l>0:
l -= 1
slow = slow.next
while fast!=slow:
fast = fast.next
slow = slow.next
return fast
return None