Marshal's confusion II

Time Limit: 1000 MS

Memory Limit: 65536 K

Total Submit: 239(80 users)

Total Accepted: 73(66 users)

Rating:

Special Judge: No

Description

one day, Marshal want to show the answer :Calculate S(n). S(n)=1^3+2^3 +3^3 +......+n^3 .

Input

Each line will contain one integer N(1 < n < 1000000000). Process to end of file.

Output

For each case, output the last four dights of S(N) in one line.

Sample Input

1 2

Sample Output

0001 0009

#include<cmath>
#include<queue>
#include<iostream>
using namespace std;
const int m=10000;
typedef long LL;
int main()
{
    LL n;
    while(~scanf("%ld",&n))//1^3+2^3+...+n^3=[n(n+1)/2]^2
    {
        LL a;
        a=n*(n+1)/2%m;
        LL sum=a*a%m;
        printf("%04d
",sum);
    }
    return 0;
}