通过当前日期，获取最近第一个周五、第二个周五、每季度末最后一个周五
def get_current_week(self, symbol: str, start_date: datetime):
i = 0
while start_date.weekday() != 4:
i = 1
start_date += timedelta(days=1)
if i:
this_week = start_date
else:
this_week = start_date + timedelta(days=7)
next_week = this_week + timedelta(days=7)
quarter = next_week + timedelta(days=7)
# 获取日期本季度第一个月(month)和最后一个月(month + 3)
month = (quarter.month - 1) - (quarter.month - 1) % 3 + 1
if month + 3 > 12:
quarter_year = quarter.year + 1
quarter_month = month + 3 -12
else:
quarter_year = quarter.year
quarter_month = month + 3
# 获取季度最后一天
this_quarter_end = datetime(quarter_year, quarter_month, 1) - timedelta(days=1)
while this_quarter_end - quarter > timedelta(days=7):
quarter += timedelta(days=7)
self.week_dic = {'CW': this_week, 'NW': next_week, 'CQ': quarter}
week = symbol.split('_')[1].split('.')[0]
return self.week_dic[week]
Pandas详解七之DatetimeIndex、PeriodIndex和TimedeltaIndex时间序列
比较好的介绍date、datetime、time、timedelta文章 https://www.cnblogs.com/chengd/articles/7291143.html
1、有一个问题，如果有一列，读取出来是如下格式，如何调整为date类型格式，将后面时、分、秒都去掉。
解答：
In [1]: from dateutil.parser import parse In [2]: parse('2011-01-03') Out[2]: datetime.datetime(2011, 1, 3, 0, 0) In [3]: parse('2011-01-03').date() Out[3]: datetime.date(2011, 1, 3)
parse('2011-01-20 23:10:33') Out[6]: datetime.datetime(2011, 1, 20, 23, 10, 33) In [7]: parse('2011-01-20 23:10') Out[7]: datetime.datetime(2011, 1, 20, 23, 10) In [8]: parse('2011-01-20 23:10').date() Out[8]: datetime.date(2011, 1, 20)
3、通过tushare获得交易日时间序列，问题一：获取到每个月第三个星期一，如果没有顺延到下一个交易日。问题二：获取每个月最后一个交易日。
In [1]: import tushare as ts In [3]: ts.trade_cal() Out[3]: calendarDate isOpen 0 1990-12-19 1 1 1990-12-20 1 2 1990-12-21 1 3 1990-12-22 0