机器人在盘内是否会相撞

 

The first line of input is K, the number of test cases. Each test case starts with one line consisting of two integers, 1 <= A, B <= 100, giving the size of the warehouse in meters. A is the length in the EW-direction, and B in the NS-direction. 
The second line contains two integers, 1 <= N, M <= 100, denoting the numbers of robots and instructions respectively. 
Then follow N lines with two integers, 1 <= Xi <= A, 1 <= Yi <= B and one letter (N, S, E or W), giving the starting position and direction of each robot, in order from 1 through N. No two robots start at the same position. 
 
Figure 1: The starting positions of the robots in the sample warehouse

Finally there are M lines, giving the instructions in sequential order. 
An instruction has the following format: 
< robot #> < action> < repeat> 
Where is one of 
  • L: turn left 90 degrees, 
  • R: turn right 90 degrees, or 
  • F: move forward one meter,

and 1 <= < repeat> <= 100 is the number of times the robot should perform this single move.

Output

Output one line for each test case: 
  • Robot i crashes into the wall, if robot i crashes into a wall. (A robot crashes into a wall if Xi = 0, Xi = A + 1, Yi = 0 or Yi = B + 1.) 
  • Robot i crashes into robot j, if robots i and j crash, and i is the moving robot. 
  • OK, if no crashing occurs.

Only the first crash is to be reported.

Sample Input

4
5 4
2 2
1 1 E
5 4 W
1 F 7
2 F 7
5 4
2 4
1 1 E
5 4 W
1 F 3
2 F 1
1 L 1
1 F 3
5 4
2 2
1 1 E
5 4 W
1 L 96
1 F 2
5 4
2 3
1 1 E
5 4 W
1 F 4
1 L 1
1 F 20

Sample Output

Robot 1 crashes into the wall
Robot 1 crashes into robot 2
OK
Robot 1 crashes into robot 2
//Memory Time 
//348K   16MS 

#include<iostream>
using namespace std;

int main(void)
{
    int cases;
    int a,b;  //A列数B行数
    int n,m;  //n : robot数, m :  指令数
    int x,y;  //robots坐标
    char dire;  //robots方向
    int rob[101],rep[101];   //rob:编号,rep:指令重复次数
    char act[101];           //act:行动指令

    bool flag=false;
    int i,k;

    int post[101][101];      //记录robot初始方向
    int num[101][101];       //记录robot的编号
    int xx[101],yy[101];     //记录robot的编号

    cin>>cases;
    while(cases--)
    {
        memset(post,-1,sizeof(post));
        memset(num,0,sizeof(num));
        memset(xx,0,sizeof(xx));
        memset(yy,0,sizeof(yy));

        cin>>a>>b;
        cin>>n>>m;

        /*Input the postion and direction of each robot*/
        for(i=1;i<=n;i++)
        {
            cin>>y>>x>>dire;   //使用cin函数时,空字符不会作为字符输入到char
            xx[i]=x;
            yy[i]=y;                  //编号记录(编号作为下标,通过编号反搜坐标)
            num[x][y]=i;              //编号记录(坐标作为下标,通过坐标反搜编号)
            if(dire=='S')             //方向记录(坐标作为下标,通过坐标反搜方向)
                post[x][y]=0;        //0 or 360     【由于坐标系改变,注意上下颠倒,即N为南,S为北,但WE不变】
            else if(dire=='E')
                post[x][y]=1;        //90
            else if(dire=='N')
                post[x][y]=2;        //180
            else if(dire=='W')
                post[x][y]=3;        //270
        }                            //用0~3代替是为了减少运算次数

        /*Input < robot #> < action> < repeat>*/
        for(k=1;k<=m;k++)
            cin>>rob[k]>>act[k]>>rep[k];

        bool flag=false;
        int row,col;
        for(k=1;k<=m;k++)
        {
            row=xx[rob[k]];
            col=yy[rob[k]];

            if(act[k]=='L')       //【由于坐标系改变,注意转向相反:L转右,R转左】
            {
                rep[k]%=4;   //角度每转4次(360度)回到原位
                post[row][col] = ( post[row][col] + rep[k] ) % 4;
            }
            else if(act[k]=='R')
            {
                rep[k]%=4;
                post[row][col] = ( post[row][col] - rep[k] ) % 4;
                if(post[row][col]<0)   //注意余数为负的情况
                    post[row][col]+=4;
            }
            else if(act[k]=='F')
            {
                if(post[row][col]==0)      //N方向移动判断
                    for(i=1;i<=rep[k];i++)
                    {
                        if(num[row-i][col]) //如果该格存在编号(即存在另外的robot)
                        {
                            cout<<"Robot "<<num[row][col]<<" crashes into robot "<<num[row-i][col]<<endl;
                            flag=true;
                            break;
                        }
                        if(row-i<1)  //判断是否撞墙
                        {
                            cout<<"Robot "<<num[row][col]<<" crashes into the wall"<<endl;
                            flag=true;
                            break;
                        }
                        if(i==rep[k])
                        {   //移动中若无任何碰撞,则把robot原坐标记录的信息更新到新坐标
                            post[row][col]=-1;   //原坐标方向重置
                            num[row][col]=0;      //原坐标编号重置
                            row-=rep[k];
                            xx[rob[k]]-=rep[k];
                            post[row][col]=0;    //新坐标方向更新
                            num[row][col]=rob[k];   //新坐标编号更新
                        }
                    }
                else if(post[row][col]==1)  //E方向移动判断
                    for(i=1;i<=rep[k];i++)
                    {
                        if(num[row][col+i])
                        {
                            cout<<"Robot "<<num[row][col]<<" crashes into robot "<<num[row][col+i]<<endl;
                            flag=true;
                            break;
                        }
                        if(col+i>a)
                        {
                            cout<<"Robot "<<num[row][col]<<" crashes into the wall"<<endl;
                            flag=true;
                            break;
                        }
                        if(i==rep[k])
                        {
                            post[row][col]=-1;
                            num[row][col]=0;
                            col+=rep[k];
                            yy[rob[k]]+=rep[k];
                            post[row][col]=1;
                            num[row][col]=rob[k];
                        }
                    }
                else if(post[row][col]==2)  //S方向移动判断
                    for(i=1;i<=rep[k];i++)
                    {
                        if(num[row+i][col])
                        {
                            cout<<"Robot "<<num[row][col]<<" crashes into robot "<<num[row+i][col]<<endl;
                            flag=true;
                            break;
                        }
                        if(row+i>b)
                        {
                            cout<<"Robot "<<num[row][col]<<" crashes into the wall"<<endl;
                            flag=true;
                            break;
                        }
                        if(i==rep[k])
                        {
                            post[row][col]=-1;
                            num[row][col]=0;
                            row+=rep[k];
                            xx[rob[k]]+=rep[k];
                            post[row][col]=2;
                            num[row][col]=rob[k];
                        }
                    }
                else if(post[row][col]==3)  //W方向移动判断
                    for(i=1;i<=rep[k];i++)
                    {
                        if(num[row][col-i])
                        {
                            cout<<"Robot "<<num[row][col]<<" crashes into robot "<<num[row][col-i]<<endl;
                            flag=true;
                            break;
                        }
                        if(col-i<1)
                        {
                            cout<<"Robot "<<num[row][col]<<" crashes into the wall"<<endl;
                            flag=true;
                            break;
                        }
                        if(i==rep[k])
                        {
                            post[row][col]=-1;
                            num[row][col]=0;
                            col-=rep[k];
                            yy[rob[k]]-=rep[k];
                            post[row][col]=3;
                            num[row][col]=rob[k];
                        }
                    }
            }
            if(flag)break;
        }
        if(!flag)
            cout<<"OK"<<endl;
    }
    return 0;
}
View Code
原文地址:https://www.cnblogs.com/baoluqi/p/3745482.html