POJ 2392 DP 多重背包

链接:

http://poj.org/problem?id=2392

代码:

 1 #include <map>
 2 #include <set>
 3 #include <cmath>
 4 #include <queue>
 5 #include <stack>
 6 #include <cstdio>
 7 #include <string>
 8 #include <vector>
 9 #include <cstdlib>
10 #include <cstring>
11 #include <sstream>
12 #include <iostream>
13 #include <algorithm>
14 #include <functional>
15 using namespace std;
16 #define rep(i,a,n) for (int i=a;i<n;i++)
17 #define per(i,a,n) for (int i=n-1;i>=a;i--)
18 #define all(x) (x).begin(),(x).end()
19 #define pb push_back
20 #define mp make_pair
21 #define lson l,m,rt<<1  
22 #define rson m+1,r,rt<<1|1 
23 typedef long long ll;
24 typedef vector<int> VI;
25 typedef pair<int, int> PII;
26 const ll MOD = 1e9 + 7;
27 const int INF = 0x3f3f3f3f;
28 const int MAXN = 4e4 + 7;
29 // head
30 
31 struct Block {
32     int h, a, c;
33     const bool operator<(const Block &t) const {
34         return a < t.a;
35     }
36 }a[410];
37 
38 int dp[MAXN];
39 int sum[MAXN];
40 
41 int main() {
42     int n;
43     cin >> n;
44     rep(i, 0, n) scanf("%d%d%d", &a[i].h, &a[i].a, &a[i].c);
45     sort(a, a + n);
46     dp[0] = 1;
47     int ans = 0;
48     rep(i, 0, n) {
49         memset(sum, 0, sizeof(sum));
50         rep(j, a[i].h, a[i].a + 1) if (!dp[j] && dp[j - a[i].h] && sum[j - a[i].h] < a[i].c) {
51             dp[j] = 1;
52             sum[j] = sum[j - a[i].h] + 1;
53             ans = max(ans, j);
54         }
55     }
56     cout << ans << endl;
57     return 0;
58 }
原文地址:https://www.cnblogs.com/baocong/p/6725303.html