Extjs/两个数组去除重复的数,求差集

                                                             
                                var allFee = new Array();// 所有的 
                                 var litFee = new Array();// 用户选择的
                                  // 剔除已有的记录
                                  forvar i = 0 ; i < feeMes.length ; i++){
                                      allFee.push( feeMes [i].feeCode );
                                  }
                                  forvar i = 0 ; i < inputMes.length ; i++){
                                      litFee.push( inputMes [i].feeCode );
                                  }
                                  forvar i = 0 ; i < allFee.length ; i++){
                                      var flag = true;
                                      for( j = 0 ; j < litFee.length ; j++){
                                          if ( allFee [i] == litFee [j] ){
                                              var flag = false;
                                          }
                                      }
                                      if ( flag ){
                                          difArray.push( i );// 不重复的feecode
                                      }
                                  }




原文地址:https://www.cnblogs.com/babyhhcsy/p/3434639.html