校验两次密码一致的js代码

function checkpasswd(){

var passwd = document.getElementByIdx_x_x_xx_x('passwd').value;

var repasswd = document.getElementByIdx_x_x_xx_x('repasswd').value;

if(passwd == repasswd){

return true;

}else{

window.alert('两次输入密码不一致');

return false;

}

}

触发:<input type='submit' name='button' id='submit' onclick='return checkpasswd()' value='确认添加'  />

原文地址:https://www.cnblogs.com/axtkdd/p/4630229.html