leetcode--Binary Tree Preorder Traversal

Given a binary tree, return the preorder traversal of its nodes' values.

For example:
Given binary tree {1,#,2,3},

   1
    
     2
    /
   3

return [1,2,3].

Note: Recursive solution is trivial, could you do it iteratively?

/**
 * Definition for binary tree
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public ArrayList<Integer> preorderTraversal(TreeNode root) {
         ArrayList<Integer> result = new ArrayList<Integer>();
        if(root != null){
            Stack<TreeNode> sta = new Stack<TreeNode>();
            sta.push(root);
            while(!sta.empty()){
                TreeNode aNode = sta.pop();
                if(aNode.right != null)
                    sta.push(aNode.right);
                if(aNode.left != null)
                    sta.push(aNode.left);
                result.add(aNode.val);
            }
        }
        return result;
    }
}