[leetcode]Simplify Path

class Solution {
public:
    string simplifyPath(string path) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        if(path.empty()) return "";
        
        if(path[path.size()-1] != '/') path += "/";
        int N = path.size();
        stack<string> s;
        string tmp;
        
        for(int i = 0; i < N; i++){
            if(path[i] == '/'){
                if(tmp == ".."){
                    if(!s.empty()) s.pop();
                }else if(!tmp.empty() && tmp != "." && tmp != ".."){
                    s.push(tmp);
                }
                tmp.clear();
        
            }else{
                tmp += path[i];
                
            }
        }
        
        //reverse stack
        stack<string> s1;
        while(!s.empty()){
            s1.push(s.top());
            s.pop();
        }
        
        string result = "";
        while(!s1.empty()){
            result += "/";
            result += s1.top();
            s1.pop();
        }
        
        return result == "" ? "/" : result;
        
    }
};


原文地址:https://www.cnblogs.com/aukle/p/3215134.html