POJ 2975 Nim(普通nim)

题目链接

#include<iostream>
#include<cstdio>
using namespace std;

int main()
{
    int n,k[1005];
    int sum,cnt;
    while(scanf("%d",&n)&&n)
    {
        sum=0,cnt=0;
        for(int i=1;i<=n;i++)
        {
            scanf("%d",&k[i]);
            sum^=k[i];
        }
        if(sum==0)
        {
            printf("0
");
            continue;
        }
        for(int i=1;i<=n;i++)
            if(k[i]>=(sum^k[i])) //sum^k[i]要加括号(),不然会WA
                cnt++;
        printf("%d
",cnt);
    }
    return 0;
}
原文地址:https://www.cnblogs.com/atmacmer/p/5244030.html