leetcode559

class Solution {
public:
    int maxDepth(Node* root) {
        int depth = 0;
        if (root != NULL)
        {
            queue<Node> Q;
            Q.push(Node(root->val, root->children));
            while (!Q.empty())
            {
                depth++;//层数自增
                vector<Node> N;
                N.clear();
                while (!Q.empty())
                {
                    Node livenode;
                    livenode = Q.front();
                    Q.pop();
                    for (auto n : livenode.children) 
                    {
                        N.push_back(Node(n->val, n->children));
                    }
                }
                
                for (auto n : N) 
                {
                    Q.push(Node(n.val, n.children));
                }
            }
        }        
        return depth;
        
    }
};

 另一种解法,递归实现:

class Solution 
{ 
public:    
    int maxDepth(Node* root) 
    { 
        if (root == NULL) 
            return 0;        
        int dep = 0; //当前节点的深度       
        for (auto n : root->children) 
        { 
            dep = max(dep, maxDepth(n)); //子节点最大深度
        }        
        return dep + 1; //子节点最大深度+当前层深度(1)
    } 
};

递归的逻辑是:当前节点的最大深度,一定是深度最大的子节点的深度+1。

原文地址:https://www.cnblogs.com/asenyang/p/9703558.html