1 func clumsy(N int) int { 2 var ary []int 3 for n := N; n >= 1; n-- { 4 ary = append(ary, n) 5 } 6 re := N % 4 //4个数字一组 7 firstgroup := true 8 //最后一组如果不够4个，就补充到4个值，*和/补充1，+和-补充0，这样结果不变 9 if re == 0 { 10 //不用补充 11 } else if re == 1 { 12 //补充3个 13 ary = append(ary, 1) //补充*1 14 ary = append(ary, 1) //补充/1 15 ary = append(ary, 0) //补充+0 16 } else if re == 2 { 17 ary = append(ary, 1) //补充/1 18 ary = append(ary, 0) //补充+0 19 } else if re == 3 { 20 ary = append(ary, 0) //补充+0 21 } 22 n := len(ary) //长度是4的倍数 23 var sum int 24 for a := 0; a <= n-4; a += 4 { 25 temp := ary[a] * ary[a+1] / ary[a+2] 26 if firstgroup { //第一组的G1*G2/G3是正 27 firstgroup = false 28 } else { 29 temp = temp * -1 //非第一组的G1*G2/G3是负 30 } 31 temp += ary[a+3] 32 sum += temp 33 } 34 return sum 35 }
这道题的思路就是把运算映射到数组的index上，形成一种规律的运算方式，在循环中进行处理。