jquery 微信端 点击物理返回按钮,弹出提示框

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>微信退出</title>
    <meta name="viewport" content="width=device-width,initial-scale=1,maximum-scale=1,user-scalable=no">
</head>
<body>
退出
<script src="scripts/jquery-1.7.1.min.js"></script>
<script>

$(function(){ 
    pushHistory(); 
    window.addEventListener("popstate", function(e) { 
// alert("我监听到了浏览器的返回按钮事件啦");//根据自己的需求实现自己的功能 
var i=confirm("你要关闭购物页面?");
if(i){
    WeixinJSBridge.call('closeWindow');
}else{
    pushHistory();
}
}, true); 
    function pushHistory() { 
        var state = { 
            title: "title", 
            url: "#"
        }; 
        window.history.pushState(state, "title", "#"); 
    } 
});
</script>
</body>
</html>
原文地址:https://www.cnblogs.com/arealy/p/7737032.html