C#迭代器实现斐波那契数列

 static IEnumerable<int> Fibs(int count)
        {
            for (int i = 0,prevFib=1,curFib=1; i < count; i++)
            {
                yield return prevFib;
                int newFib = prevFib + curFib;
                prevFib = curFib;
                curFib = newFib;
            }
        }
原文地址:https://www.cnblogs.com/aqgy12138/p/12642189.html