java collections读书笔记(4) stack

stack,是先进后出的一个堆栈,可是,因为他继承自vector,所以,vector很多功能他都具有。

stack和vector的关系应该是 has-a,而不是is-a

简单的操作有,push,top等

见例子如下:

import java.util.Stack;
public class StackExample {
public static void main (String args[]) {
Stack s = new Stack();
s.push("Autumnal Tints");
s.push("A Week on the Concord and Merrimack Rivers");
s.push("The Maine Woods");
// Check out what's next to read
System.out.println("Next: " + s.peek());
s.push("Civil Disobedience, Solitude and Life Without Principle");
// Read a book
System.out.println(s.pop());
s.push("Walden");
s.push("The Natural Man");
// Find that other book
int count = s.search("The Maine Woods");
while (count != −1 && count > 1) {
s.pop();
count−;
}
// Read a book
System.out.println(s.pop());
// Anything left?
System.out.println(s.empty());
}
}

看看源代码,不复杂:

public
class Stack<E> extends Vector<E> {
    /**
     * Creates an empty Stack.
     */
    public Stack() {
    }

    /**
     * Pushes an item onto the top of this stack. This has exactly
     * the same effect as:
     * <blockquote><pre>
     * addElement(item)</pre></blockquote>
     *
     * @param   item   the item to be pushed onto this stack.
     * @return  the <code>item</code> argument.
     * @see     java.util.Vector#addElement
     */
    public E push(E item) {
        addElement(item);

        return item;
    }

    /**
     * Removes the object at the top of this stack and returns that
     * object as the value of this function.
     *
     * @return  The object at the top of this stack (the last item
     *          of the <tt>Vector</tt> object).
     * @throws  EmptyStackException  if this stack is empty.
     */
    public synchronized E pop() {
        E       obj;
        int     len = size();

        obj = peek();
        removeElementAt(len - 1);

        return obj;
    }

    /**
     * Looks at the object at the top of this stack without removing it
     * from the stack.
     *
     * @return  the object at the top of this stack (the last item
     *          of the <tt>Vector</tt> object).
     * @throws  EmptyStackException  if this stack is empty.
     */
    public synchronized E peek() {
        int     len = size();

        if (len == 0)
            throw new EmptyStackException();
        return elementAt(len - 1);
    }

    /**
     * Tests if this stack is empty.
     *
     * @return  <code>true</code> if and only if this stack contains
     *          no items; <code>false</code> otherwise.
     */
    public boolean empty() {
        return size() == 0;
    }

    /**
     * Returns the 1-based position where an object is on this stack.
     * If the object <tt>o</tt> occurs as an item in this stack, this
     * method returns the distance from the top of the stack of the
     * occurrence nearest the top of the stack; the topmost item on the
     * stack is considered to be at distance <tt>1</tt>. The <tt>equals</tt>
     * method is used to compare <tt>o</tt> to the
     * items in this stack.
     *
     * @param   o   the desired object.
     * @return  the 1-based position from the top of the stack where
     *          the object is located; the return value <code>-1</code>
     *          indicates that the object is not on the stack.
     */
    public synchronized int search(Object o) {
        int i = lastIndexOf(o);

        if (i >= 0) {
            return size() - i;
        }
        return -1;
    }

    /** use serialVersionUID from JDK 1.0.2 for interoperability */
    private static final long serialVersionUID = 1224463164541339165L;
}

原文地址:https://www.cnblogs.com/aomi/p/3135368.html