[Leetcode] DP-- 95. Unique Binary Search Trees II

 Given an integer n, generate all structurally unique BST's (binary search trees) that store values 1...n.

For example,
Given n = 3, your program should return all 5 unique BST's shown below.

   1         3     3      2      1
           /     /      /       
     3     2     1      1   3      2
    /     /                        
   2     1         2                 3

Solution:

this is a little difficult than the "96 Unique Binary Search Trees I"
it requires to get all the unique binary search tree stored.

1. 1st try to use iterative way

define dpT[i] indicate the treenodes stored in last all rooted as i

dpT[i] 
dpT[0] = []
dpT[1] = [TreeNode(1)]
 
 dp[2]  =  dp[0]*dp[1] +  dp[1]*dp[0]
 
for e in dpT[1]
    t2 = TreeNode(2)
    t2.right = e
    dpT[2].append(t2)
  
for e in dpT[1]
    t1 = TreeNode(1)
    t1.left = e
    dpT[2].append(t1)
 
 
dp[3]  =  dp[0]*dp[2]  + dp[1]*dp[1]  + dp[2]*dp[0]
 
if i == 0:
for e in dpT[2]                         //k-i-1
    root = TreeNode(1)             // 1
    root.right = e
    dpT[3].append(root)        //k
else if i == 2:                                      //k-1
for e in dpT[2]                       //i
    root = TreeNode(3)               // k
    root.left = e                           
    dpT[3].append(root)                //k
 
else:
      for e1 in dpT[1]:                                 //i
           for e2 in dpT[1]:                           //k-i-1
               root = TreeNode(2]          // i    e.g. 2 is the second element important
               root.left = e1
               root.right = e2
           dpT[3].append(root)                 //k
 
 
 
2. use recursive way

leftsubtree (1, k-1) 
root (k)
rightsubtree(k+1, n)
 1  def generateTreeHelper(left, right):
 2             lst = []
 3             if left > right:
 4                 lst.append(None)
 5                 return lst
 6             
 7             for i in range(left, right+1, 1):
 8                 lSubTree = generateTreeHelper(left, i-1)
 9                 rSubTree = generateTreeHelper(i+1, right)
10                 for j in range(0, len(lSubTree)):
11                     for k in range(0, len(rSubTree)):
12                         root = TreeNode(i)
13                         root.left = lSubTree[j]
14                         root.right = rSubTree[k]
15                         lst.append(root)
16             return lst
17         if n == 0:
18             return []
19         return generateTreeHelper(1, n)
原文地址:https://www.cnblogs.com/anxin6699/p/7131849.html