怎么将对象里面部分的属性放到一个空的对象里面去

  var obj={
        name:'jack',
        age:18,
        sex:'male'
    }
    var {name,age}=obj
    var obj2={name,age}
    console.log(obj2) //{name: "jack", age: 18}

这是es6的用法

还有其他的3种方法,关于对象复制的
es6

 var obj = {
       name: 'jack',
       age: 18
     }
     var data =  Object.assign(obj)
     console.log(data) //{name: 'jack',age: 18}
     data.name = '花花'
     console.log(data)//{name: "花花", age: 18}
     console.log(obj)//{name: "花花", age: 18}

for in

 var obj = {  
       name: 'jack',
       age: 18
     }
     var params = {}
     for(var key in obj){
      params[key] = obj[key]
     }
     console.log(params, 22)/

或者

  var obj = {  
       name: 'jack',
       age: 18,
       hobby: {
         school: 'listen video',
         home: 'watch TV'
       }
     }
     var params = {}
     params =JSON.parse(JSON.stringify(obj))
原文地址:https://www.cnblogs.com/antyhouse/p/10006618.html