python实现冒泡排序

list = [3, 2, 1, 9, 10, 78,6]
n = len(list)

for i in range(n):
    for j in range(0,n-i-1):
        if list[j]> list[j+1]:
            list[j],list[j+1] = list[j+1], list[j]
print(list)

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原文地址:https://www.cnblogs.com/anthinia/p/13840095.html