istringstream的操作

今天在stackoverflow上看到这么个问题,写完之后看了看别人的提交的答案,感觉自己的答案虽然能得出正确结果但是有点啰嗦,对于c++还是没有熟练,没有想起有istringstream,而且提问的老外写的程序bug实在是太多了,while循环啊,分号啊都不规范,不过那个return挺有意思,嘿嘿第一次见(可能是写的代码和看的代码太少了吧 ,嘿嘿 ,见笑,我也是一菜),于是我放弃了我原来的答案,修改了一下别人的答案,那个人的答案也不对,不能运行啊,所以说我自己改动了一下.

今儿记录一下,省的以后忘..

老外的提问:

 1 struct client
 2 {
 3     string PhoneNumber;
 4     string FirstName;
 5     string LastName;
 6     string Age;
 7 };
 8 int main()
 9 {
10     string data = getClientDatabase();
11 
12     vector <client> clients;
13 
14     parse_string(data, clients);
15     return 0;
16 }
17 
18 string getClientDatabase()
19 {
20     return
21         "(844)615-4504 Sofia Ross 57 \n"
22         "(822)516-8895 Jenna Doh 30 \n"
23         "(822)896-5453 Emily Saks 43 \n"
24 
25 }
26 
27 void parse_string(string data, vector <client> &clients)
28 {
29     string temp;
30     string temp1;
31     string temp2;
32     string temp3;
33 
34     int i = 0;
35     int j = 0;
36     int k = 0;
37     int l = 0;
38 
39     while (i < data.length())
40     {
41         if (data.at(i) != ' ')
42         {
43             temp.push_back(data.at(i));
44             j++;
45         }
46         else
47         {
48             clients.at(i).PhoneNumber = temp;
49         }
50 
51     }
52     if (data.at(j) != ' ')
53     {
54         temp1.push_back(data.at(j));
55         k++;
56     }
57     else
58     {
59         clients.at(i).FirstName = temp1;
60     }
61 
62     if (data.at(k) != ' ')
63     {
64         temp2.push_back(data.at(k));
65         l++;
66     }
67     else
68     {
69         clients.at(i).LastName = temp2;
70     }
71 
72     if (data.at(l) != ' ')
73     {
74         temp3.push_back(data.at(l));
75 
76     }
77     else
78     {
79         clients.at(i).Age = temp3;
80     }
81     i++;
82 
83 }

我的回答:

 1 void parse_string(string data, vector <client> & clients)
 2  {
 3      struct client tempS;
 4      istringstream iss(data);
 5      for (size_t i=0; iss >> tempS.PhoneNumber; ++i)
 6      {
 7          iss >> tempS.FirstN >> tempS.LastN >> tempS.Age;
 8          clients.push_back(tempS);
 9      }
10  }
11 //test code
12 
13 vector <client>::iterator it = clients.begin();
14      for(; it != clients.end(); ++it )
15     {
16         cout << it->PhoneNumber << " "
17              << it->FirstN << " "
18              << it->LastN << " "
19              << it->Age << endl;
20     }