集合 相关 深浅copy

''
集合:可变的数据类型,他里面的元素必须是不可变的数据类型,无序,不重复。
     {}
'''
# set1 = set({1,2,3})
# set2 = {1,2,3,[2,3],{'name':'alex'}}  # 错的  集合和字典是可变数据类型
# print(set1)
# print(set2)
# set1 = {'alex','wusir','ritian','egon','barry',}
#
#add
# set1.add('女神')
# print(set1)
#update   #迭代增加
# set1.update('abc')
# print(set1)
#删除

# set1.pop()  # 随机删除
# print(set1.pop())  # 有返回值
# print(set1)

# set1.remove('alex')  # 按元素
# print(set1)

#空字典{}    空集合set()
# set1.clear()
# print(set1)  # set()

# del set1   #删除集合
# print(set1)

#
# for i in set1:
#     print(i)

# set1 = {1,2,3,4,5} # set2 = {4,5,6,7,8} # set3 = set1 & set2 #交集 # print(set3) # {4, 5} # print(set1.intersection(set2)) # {4, 5} # set1 = {1,2,3,4,5} # set2 = {4,5,6,7,8} # print(set1 | set2) # {1, 2, 3, 4, 5, 6, 7,8} #并集 # print(set2.union(set1)) # {1, 2, 3, 4, 5, 6, 7} # set1 = {1,2,3,4,5} # set2 = {4,5,6,7,8} # print(set1 ^ set2) # {1, 2, 3, 6, 7, 8} # print(set1.symmetric_difference(set2)) # {1, 2, 3, 6, 7, 8} # set1 = {1,2,3,4,5} # set2 = {4,5,6,7,8} # print(set1 - set2) # {1, 2, 3} #差集 # #set1独有的 # print(set1.difference(set2)) # {1, 2, 3} # set1 = {1,2,3,} # set2 = {1,2,3,4,5,6} # # print(set1 < set2) # print(set1.issubset(set2)) # 这两个相同,都是说明set1是set2子集。 # print(set2 > set1) # print(set2.issuperset(set1)) # 这两个相同,都是说明set2是set1超集。 #去重 # li = [1,2,33,33,2,1,4,5,6,6] # set1 = set(li) # # print(set1) # li = list(set1) # print(li) # s1 = {1,2,3} # print(s1,type(s1)) # s = frozenset('barry') # print(s,type(s)) # for i in s: # print(i)

深浅copy

# 赋值运算
# l1 = [1,2,3]
# l2 = l1
# l1.append('a')
# print(l1,l2)

#copy
# l1 = [1,2,3]
# l2 = l1.copy()
# print(l1,l2)
# print(id(l1),id(l2))
# l2.append('a')
# print(l1,l2)

# l1 = [1,2,[4,5,6],3]
# l2 = l1.copy()
#
# print(l1,id(l1))
# print(l2,id(l2))
# l1.append('a')
# print(l1,l2)
# l1[2].append('a')
# print(l1,l2)
# print(id(l1[2]))
# print(id(l2[2]))
import copy
# l1 = [1,2,[4,5,6],3]
# l2 = copy.deepcopy(l1)
# print(l1,id(l1))
# print(l2,id(l2))
# l1[2].append('a')
# print(l1,l2)

# l1 = [1,[1],2,3,4]
# l2 = l1
# # l1[1].append('a')
# # l2 的结果是什么?
#
#
# print(l1,id(l1))
# print(l2,id(l2))
# print(l1[1] is l2[1])

 enumerate 用法

# li = ['alex','taibai','wusir','egon']
# for i in li:
#     print(li.index(i),i)

# for index,i in enumerate(li,1):
#     print(index,i)
原文地址:https://www.cnblogs.com/aj-AJ/p/10798599.html