2005

给出一个日期计算当天是该年的第几天

看了参考答案之后至于闰年怎么定义就不讨论了

我的心情是这样的：笨笨笨笨笨

 1 #include <stdio.h>
 2 int leap();
 3 int main()
 4 {
 5     int year,month,day,sum;
 6     int leapYear[12] = {31,29,31,30,31,30,31,31,30,31,30,31};
 7     int NleapYear[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
 8     while(scanf("%d/%d/%d",&year,&month,&day))
 9     {
10         sum = 0;
11         switch (leap(year)) {
12         case 0:
13             while(month > 1)
14             {
15                 month --;
16                 sum += NleapYear[month - 1];
17             }
18             sum += day;
19             break;
20         default:
21             while(month > 1)
22             {
23                 month --;
24                 sum += leapYear[month - 1];
25             }
26             sum += day;
27             break;
28         }
29         printf("%d
",sum);
30     }
31 
32     return 0;
33 }
34 
35 int leap(int a)
36 {
37     if(a /400 == 0 || (a /4 == 0 && a /400 != 0))
38         return 1;
39     else
40         return 0;
41 }

参考c++

 1 #include <math.h>
 2 #include <stdio.h>
 3 
 4 #define lev(n) (n % 4 == 0 && (n % 100 != 0 || n % 400 == 0))
 5 
 6 int main(void)
 7 {
 8     int y, m, d, i, s;
 9     int month[2][13] = {
10         {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
11         {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
12     };
13 
14     while (scanf("%d/%d/%d", &y, &m, &d) != EOF)
15     {
16         for (s = 0, i = 1 ; i < m ; i++)
17             s += month[lev(y)][i];
18         s += d;
19         printf("%d
", s);
20     }
21 
22     return 0;
23 }

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