ORACLE11G常用函数

1 单值函数
1.1 日期函数

1.1.1 Round

[舍入到最接近的日期](day:舍入到最接近的星期日)

   select sysdate S1, 
   round(sysdate) S2 , 
   round(sysdate,'year') YEAR, 
   round(sysdate,'month') MONTH , 
   round(sysdate,'day') DAY from dual;

S1 S2 YEAR MONTH DAY

------------------- ------------------- ------------------- ------------------- -------------------

2014-03-17 14:11:40 2014-03-18 00:00:00 2014-01-01 00:00:00 2014-04-01 00:00:00 2014-03-16 00:00:00

1.1.2 Trunc

[截断到最接近的日期,单位为天] ,返回的是日期类型

   select sysdate S1,                      
     trunc(sysdate) S2,                 --返回当前日期,无时分秒 
     trunc(sysdate,'year') YEAR,        --返回当前年的1月1日,无时分秒 
     trunc(sysdate,'month') MONTH ,     --返回当前月的1日,无时分秒 
     trunc(sysdate,'day') DAY           --返回当前星期的星期天,无时分秒 
   from dual;

S1 S2 YEAR MONTH DAY

------------------- ------------------- ------------------- ------------------- -------------------

2014-03-17 14:20:17 2014-03-17 00:00:00 2014-01-01 00:00:00 2014-03-01 00:00:00 2014-03-16 00:00:00

1.1.3 查找月的第一天,最后一天

SELECT Trunc(Trunc(SYSDATE, 'MONTH') - 1, 'MONTH') First_Day_Last_Month,
       Trunc(SYSDATE, 'MONTH') - 1 / 86400 Last_Day_Last_Month,
       Trunc(SYSDATE, 'MONTH') First_Day_Cur_Month,
       LAST_DAY(Trunc(SYSDATE, 'MONTH')) + 1 - 1 / 86400 Last_Day_Cur_Month
   FROM dual;

FIRST_DAY_LAST_MONT LAST_DAY_LAST_MONTH FIRST_DAY_CUR_MONTH LAST_DAY_CUR_MONTH

------------------- ------------------- ------------------- -------------------

2014-02-01 00:00:00 2014-02-28 23:59:59 2014-03-01 00:00:00 2014-03-31 23:59:59

1.1.4 ADD_MONTHS

增加或减去月份

select add_months(trunc(sysdate,'month'),2),add_months(trunc(sysdate,'month'),-13) from dual;

ADD_MONTHS(TRUNC(SY ADD_MONTHS(TRUNC(SY

------------------- -------------------

2014-05-01 00:00:00 2013-02-01 00:00:00

1.1.5 LAST_DAY

返回日期的最后一天

HR@test> select last_day(sysdate) from dual;

LAST_DAY(SYSDATE)

-------------------

2014-03-31 14:28:03

1.1.6 MONTHS_BETWEEN(date2,date1)

给出date2-date1的月份

HR@test>select trunc(months_between(to_date('20141001','yyyy-mm-dd'),sysdate)) mon_betw from dual;

MON_BETW

----------

6

1.1.7 NEXT_DAY(date,day)

给出日期date和星期x之后计算最近一个星期的日期。day为1-7或星期日-星期六,1表示星期日。 next_day(sysdate,6)是从当前开始下一个星期五。后面的数字是从星期日开始算起。
   1 2 3 4 5 6 7     
日 一 二 三 四 五 六

   Monday-Sunday, for format code DAY      
    Mon-Sun, for format code DY      
    1-7, for format code D  

HR@test>select next_day(sysdate,2) next_day from dual;

NEXT_DAY

-------------------

2014-03-24 14:39:03

HR@test>select next_day(sysdate,'mon') next_day from dual;

NEXT_DAY

-------------------

2014-03-24 14:40:27

1.1.8 SYSDATE

用来得到系统的当前日期

HR@test>select to_char(sysdate,'dd-mm-yyyy day') from dual;

TO_CHAR(SYSDATE,'DD-MM-YYYYDAY')

----------------------------------------------------------------------------------------------

17-03-2014 monday

1.1.9 extract

     extract()找出日期或间隔值的字段值

HR@test>SELECT EXTRACT(HOUR FROM TIMESTAMP '2001-02-16 2:38:40') from dual;

EXTRACT(HOURFROMTIMESTAMP'2001-02-162:38:40')

---------------------------------------------

2

OE@test>SELECT EXTRACT(month FROM order_date) "Month", COUNT(order_date) "No. of Orders"

2 FROM oe.orders

3 GROUP BY EXTRACT(month FROM order_date)

4 ORDER BY "No. of Orders" DESC, "Month";

Month No. of Orders

---------- -------------

11 16

6 14

7 14

3 11

9 11

5 10

2 9

1 5

8 5

10 5

12 4

4 1

select sysdate ,to_char(sysdate,'hh') ,to_char(sysdate,'hh24') from dual;

SYSDATE TO_C TO_C

----------------------- ---- ----

17-MAR-2014 14:53:23 02 14

1.2 字符函数
2 CONCAT

连接两个字符串;

select concat(concat(LAST_NAME,'.'),FIRST_NAME) from employees;

CONCAT(CONCAT(LAST_NAME,'.'),FIRST_NAME)

--------------------------------------------------------------------------------------------

Abel.Ellen

Ande.Sundar

Atkinson.Mozhe

Austin.David

Baer.Hermann

Baida.Shelli

Banda.Amit

Bates.Elizabeth

Bell.Sarah

Bernstein.David

Bissot.Laura

Bloom.Harrison

Bull.Alexis

Cabrio.Anthony

Cambrault.Gerald

Cambrault.Nanette

……

2.1.1 INITCAP

返回字符串并将字符串中每一个单词的首字母变为大写,其他字符小写。单词有空格或非字母的字符隔开

HR@test>select initcap('LAKALA'),initcap('lakala'),initcap('la1ka?la'),initcap('la ka la') from dual;

INITCAP('LAK INITCAP('LAK INITCAP('LA1KA?L INITCAP('LAKALA'

------------ ------------ ---------------- ----------------

Lakala Lakala La1ka?La La Ka La

2.1.2 INSTR(C1,C2,I,J)

在一个字符串中搜索指定的字符,返回发现指定的字符的位置;
C1 被搜索的字符串
C2 希望搜索的字符串
I 搜索的开始位置,默认为1
J 出现的位置,默认为1

HR@test>select instr('lakala LAKALA','la',1,1),instr('lakala LAKALA','la',1,2) instring from dual;

INSTR('LAKALALAKALA','LA',1,1) INSTRING

------------------------------ ----------

1 5

2.1.3 LENGTH

返回字符串的长度;

SQL> select length(null),length(''),length(' '),length('lakala') from dual;

LENGTH(NULL) LENGTH('') LENGTH('') LENGTH('LAKALA')

------------ ---------- ---------- ----------------

1 6

2.1.4 LOWER

返回字符串,并将所有的字符小写

SYS@test> select lower('LaKaLa') from dual;

LOWER('LAKAL

------------

lakala

2.1.5 UPPER

返回字符串,并将所有的字符大写

SYS@test> select upper('LaKaLa') from dual;

UPPER('LAKAL

------------

LAKALA

2.1.6 RPAD和LPAD

(填充字符)RPAD 在列的右边填充字符/LPAD 在列的左边填充字符

SYS@test>select rpad('lakala',10,'#'), lpad('222.111',10,'0')from dual;

RPAD('LAKALA',10,'#' LPAD('222.111',10,'0

-------------------- --------------------

lakala#### 000222.111

2.1.7 LTRIM和RTRIM/ TRIM(s from string)

LTRIM 删除左边出现的字符串,RTRIM 删除右边出现的字符串.

LEADING 剪掉前面的字符
TRAILING 剪掉后面的字符
如果不指定,默认为空格符

SYS@test>select rtrim('#la#ka#la###','#'),ltrim('###la#ka#la#','#'),trim( '#' from '###la#ka#la###') from dual;

RTRIM('#LA#KA#LA## LTRIM('###LA#KA#LA TRIM('#'FROM'###

------------------ ------------------ ----------------

#la#ka#la la#ka#la# la#ka#la

2.1.8 SUBSTR(string,start,count)

取子字符串,从start开始,取count个

SYS@test>select substr('010-56710999',1,4),substr('010-56710999',5,8) from dual;

SUBSTR(' SUBSTR('010-5671

-------- ----------------

010- 56710999

2.1.9 REPLACE(string,s1,s2)

string 希望被替换的字符或变量
s1 被替换的字符串
s2 要替换的字符串

SYS@test>select replace('la#ka#la','#','') from dual;

REPLACE('LA#

------------

lakala

2.2 数字函数
3 ABS

返回指定值的绝对值

SYS@test>select abs(100),abs(-100) from dual;

ABS(100) ABS(-100)

---------- ----------

100 100

3.1.1 FLOOR

对给定的数字取整数

SYS@test>select floor(11.92),floor(-11.02) from dual;

FLOOR(11.92) FLOOR(-11.02)

------------ -------------

11 -12

3.1.2 MOD(n1,n2)

返回一个n1除以n2的余数

SYS@test> select mod(12,3),mod(1,3),mod(2,3) from dual;

MOD(12,3) MOD(1,3) MOD(2,3)

---------- ---------- ----------

0 1 2

3.1.3 ROUND和TRUNC

按照指定的精度进行舍入

SYS@test> select round(11.9),round(-11.4),trunc(11.9),trunc(-11.1) from dual;

ROUND(11.9) ROUND(-11.4) TRUNC(11.9) TRUNC(-11.1)

----------- ------------ ----------- ------------

12 -11 11 -11

3.1.4 SIGN

取数字n的符号,大于0返回1,小于0返回-1,等于0返回0

SYS@test>select sign(12),sign(-12),sign(0) from dual;

SIGN(12) SIGN(-12) SIGN(0)

---------- ---------- ----------

1 -1 0

3.1.5 TRUNC

按照指定的精度截取一个数

SYS@test>select trunc(11124.1888,-2) trunc1,trunc(111124.1888,2) from dual;

TRUNC1 TRUNC(111124.1888,2)

---------- --------------------

11100 111124.18

3.2 转换函数

TO_DATE格式(以时间:2007-11-02   13:45:25为例)
        Year:      
        yy two digits 两位年 显示值:07
        yyy three digits 三位年 显示值:007
        yyyy four digits 四位年 显示值:2007
        Month:      
        mm    number     两位月 显示值:11
        mon    abbreviated 字符集表示 显示值:11月,若是英文版,显示nov     
        month spelled out 字符集表示 显示值:11月,若是英文版,显示november 
        Day:      
        dd    number         当月第几天 显示值:02
        ddd    number         当年第几天 显示值:02
        dy    abbreviated 当周第几天简写 显示值:星期五,若是英文版,显示fri
        day    spelled out   当周第几天全写 显示值:星期五,若是英文版,显示friday      

D Day of week (1-7). This element depends on the NLS territory of the session.

              Hour:
              hh    two digits 12小时进制 显示值:01
              hh24 two digits 24小时进制 显示值:13
              Minute:
              mi    two digits 60进制 显示值:45
              Second:
              ss    two digits 60进制 显示值:25
其它
              Q     digit         季度 显示值:4
              WW    digit         当年第几周 显示值:44
              W    digit          当月第几周 显示值:1
        24小时格式下时间范围为: 0:00:00 - 23:59:59....      
        12小时格式下时间范围为: 1:00:00 - 12:59:59 ....

4 TO_CHAR(date,format)

SYS@test>select to_char(sysdate,'WW W Q ddd D'),sysdate from dual;

TO_CHAR(SYSDATE,'WWWQDDD SYSDATE

------------------------ -----------------------

11 3 1 076 2 17-MAR-2014 16:53:41

select to_char(sysdate,'yyyy-mm-dd hh24:mi:ss') as nowTime from dual;   //日期转化为字符串
select to_char(sysdate,'yyyy') as nowYear   from dual;   //获取时间的年
select to_char(sysdate,'mm')    as nowMonth from dual;   //获取时间的月
select to_char(sysdate,'dd')    as nowDay    from dual;   //获取时间的日
select to_char(sysdate,'hh24') as nowHour   from dual;   //获取时间的时
select to_char(sysdate,'mi')    as nowMinute from dual;   //获取时间的分
select to_char(sysdate,'ss')    as nowSecond from dual;   //获取时间的秒

4.1.1 TO_DATE(string,format)

将字符串转化为ORACLE中的一个日期

4.1.2 TO_NUMBER

将给出的字符转换为数字

SYS@test>select to_number('2014') year from dual;

YEAR

----------

2014

4.2 Null函数

NVL(expr1, expr2)->expr1为NULL,返回expr2;不为NULL,返回expr1。注意两者的类型要一致.

NVL2 (expr1, expr2, expr3) ->expr1不为NULL,返回expr2;为NULL,返回expr3。expr2和expr3类型不同的话,expr3会转换为expr2的类型 .

NULLIF (expr1, expr2) ->相等返回NULL,不等返回expr1.

5 nvl(ex1,ex2):

ex1值为空则返回ex2,否则返回该值本身ex1(常用)

例:如果雇员没有佣金,将显示0,否则显示佣金

    SCOTT@test>select comm,nvl(comm,0) from emp;

COMM NVL(COMM,0)

---------- -----------

0

300 300

500 500

0

1400 1400

0

0

0

0

0 0

0

0

0

0

5.1.1 nvl2(ex1,ex2,ex3) :

如果ex1不为空,显示ex2,否则显示ex3

HR@test>SELECT last_name, salary,

2 NVL2(commission_pct, salary + (salary * commission_pct), salary) income

3 FROM hr.employees

4 WHERE last_name like 'B%'

5 ORDER BY last_name;

LAST_NAME SALARY INCOME

-------------------------------------------------- ---------- ----------

Baer 10000 10000

Baida 2900 2900

Banda 6200 6820

Bates 7300 8395

Bell 4000 4000

Bernstein 9500 11875

Bissot 3300 3300

Bloom 10000 12000

Bull 4100 4100

5.1.2 nullif(ex1,ex2):

值相等返空,否则返回第一个值

HR@test>SELECT e.last_name, NULLIF(e.job_id, j.job_id) "Old Job ID"

2 FROM employees e, job_history j

3 WHERE e.employee_id = j.employee_id

4 ORDER BY last_name, "Old Job ID";

LAST_NAME Old Job ID

-------------------------------------------------- --------------------

De Haan AD_VP

Hartstein MK_MAN

Kaufling ST_MAN

Kochhar AD_VP

Kochhar AD_VP

Raphaely PU_MAN

Taylor SA_REP

Taylor

Whalen AD_ASST

Whalen

5.1.3 coalesce:

返回列表中第一个非空表达式

OE@test>SELECT product_id, list_price, min_price,

2 COALESCE(0.9*list_price, min_price, 5) "Sale"

3 FROM product_information

4 WHERE supplier_id = 102050

5 ORDER BY product_id;

PRODUCT_ID LIST_PRICE MIN_PRICE Sale

---------- ---------- ---------- ----------

1769 48 43.2

1770 73 73

2378 305 247 274.5

2382 850 731 765

3355 5

5.2 其他函数
6 Decode

[实现if ..then 逻辑]   注:第一个是表达式,最后一个是不满足任何一个条件的值

SCOTT@test>select deptno,decode(deptno,10,'1',20,'2',30,'3','??') from dept;

DEPTNO DECO

---------- ----

10 1

20 2

30 3

40 ??

SELECT product_id,

DECODE (warehouse_id, 1, 'Southlake',

2, 'San Francisco',

3, 'New Jersey',

4, 'Seattle',

'Non domestic') "Location"

FROM oe.inventories

WHERE product_id < 1775

ORDER BY product_id, "Location";

PRODUCT_ID Location

---------- --------------------------

1729 New Jersey

1729 Non domestic

1729 Non domestic

1729 Non domestic

1729 Non domestic

1729 Non domestic

1733 New Jersey

1733 Non domestic

1733 Non domestic

1733 Non domestic

1733 Non domestic

1733 Non domestic

1733 San Francisco

1733 Seattle

1733 Southlake

1734 New Jersey

……

6.1.1 Case

[实现switch ..case 逻辑]注:CASE语句在处理类似问题就显得非常灵活。当只是需要匹配少量数值时,用Decode更为简洁。

OE@test>SELECT cust_last_name,

2 CASE credit_limit WHEN 100 THEN 'Low'

3 WHEN 5000 THEN 'High'

4 ELSE 'Medium' END AS credit

5 FROM customers

6 ORDER BY cust_last_name, credit;

CUST_LAST_NAME CREDIT

---------------------------------------- ------------

Adjani Medium

Adjani Medium

Alexander Medium

Alexander Medium

Altman High

Altman Medium

Altman Medium

Andrews Medium

Andrews Medium

Ashby High

Ashby High

Aykroyd Medium

Baldwin Medium

…….

7 聚合函数
8 Rollup/cube

rollup 按分组的第一个列进行统计和最后的小计
    cube 按分组的所有列的进行统计和最后的小计

SCOTT@test>select deptno,job ,sum(sal) from emp group by deptno,job;

DEPTNO JOB SUM(SAL)

---------- ------------------ ----------

20 CLERK 1900

30 SALESMAN 5600

20 MANAGER 2975

30 CLERK 950

10 PRESIDENT 1000

30 MANAGER 2850

10 CLERK 1000

10 MANAGER 1000

20 ANALYST 6000

SCOTT@test>select deptno,job ,sum(sal) from emp group by rollup(deptno,job);

DEPTNO JOB SUM(SAL)

---------- ------------------ ----------

10 CLERK 1000

10 MANAGER 1000

10 PRESIDENT 1000

10 3000

20 CLERK 1900

20 ANALYST 6000

20 MANAGER 2975

20 10875

30 CLERK 950

30 MANAGER 2850

30 SALESMAN 5600

30 9400

23275

SCOTT@test>select deptno,job ,sum(sal) from emp group by rollup(job,deptno);

DEPTNO JOB SUM(SAL)

---------- ------------------ ----------

10 CLERK 1000

20 CLERK 1900

30 CLERK 950

CLERK 3850

20 ANALYST 6000

ANALYST 6000

10 MANAGER 1000

20 MANAGER 2975

30 MANAGER 2850

MANAGER 6825

30 SALESMAN 5600

SALESMAN 5600

10 PRESIDENT 1000

PRESIDENT 1000

23275

    cube 产生组内所有列的统计和最后的小计

    SCOTT@test>select deptno,job ,sum(sal) from emp group by cube(deptno,job);

DEPTNO JOB SUM(SAL)

---------- ------------------ ----------

23275

CLERK 3850

ANALYST 6000

MANAGER 6825

SALESMAN 5600

PRESIDENT 1000

10 3000

10 CLERK 1000

10 MANAGER 1000

10 PRESIDENT 1000

20 10875

20 CLERK 1900

20 ANALYST 6000

20 MANAGER 2975

30 9400

30 CLERK 950

30 MANAGER 2850

30 SALESMAN 5600

8.1.1 AVG(DISTINCT|ALL)

all表示对所有的值求平均值,distinct只对不同的值求平均值

HR@test>SELECT AVG(salary) "Average"

2 FROM employees;

Average

----------

6461.83178

8.1.2 MAX(DISTINCT|ALL)

求最大值,ALL表示对所有的值求最大值,DISTINCT表示对不同的值求最大值,相同的只取一次

HR@test>SELECT MAX(salary) "Maximum"

2 FROM employees;

Maximum

----------

24000

8.1.3 MIN(DISTINCT|ALL)

求最小值,ALL表示对所有的值求最小值,DISTINCT表示对不同的值求最小值,相同的只取一次

HR@test>SELECT MIN(hire_date) "Earliest"

2 FROM employees;

Earliest

-----------------------

13-JAN-2001 00:00:00

8.1.4 COUNT

功能描述:对一组内发生的事情进行累积计数,如果指定*或一些非空常数,count将对所有行计数,如果指定一个表达式,count返回表达式非空赋值的计数,当有相同值出现时,这些相等的值都会被纳入被计算的值;可以使用DISTINCT来记录去掉一组中完全相同的数据后出现的行数。.

整个结果集是一个组
   1) 求部门30 的最高工资,最低工资,平均工资,总人数,有工作的人数,工种数量及工资总和

SCOTT@test> select max(ename),max(sal),

2 min(ename),min(sal),

3 avg(sal),

4 count(*) ,count(job),count(distinct(job)) ,

5 sum(sal) from emp where deptno=30;

MAX(ENAME) MAX(SAL) MIN(ENAME) MIN(SAL) AVG(SAL) COUNT(*) COUNT(JOB) COUNT(DISTINCT(JOB)) SUM(SAL)

-------------------- ---------- -------------------- ---------- ---------- ---------- ---------- -------------------- ----------

WARD 2850 ALLEN 950 1566.66667 6 6 3 9400

9 分析函数
9.1 分析函数语法:

analytic_function([ arguments ]) OVER ([ query_partition_clause ] [ order_by_clause [ windowing_clause ] ])

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例:
sum(sal) over (partition by deptno order by ename) new_alias
sum就是函数名,(sal)是分析函数的参数,每个函数有0~3个参数,参数可以是表达式,例如:sum(sal+comm),over 是一个关键字,用于标识分析函数,否则查询分析器不能区别sum()聚集函数和sum()分析函数,partition by deptno 是可选的分区子句,如果不存在任何分区子句,则全部的结果集可看作一个单一的大区。order by ename 是可选的order by 子句,有些函数需要它,有些则不需要.依靠已排序数据的那些函数,如:用于访问结果集中前一行和后一行的LAG和LEAD,必须使用,其它函数,如AVG,则不需要.在使用了任何排序的开窗函数时,该子句是强制性的,它指定了在计算分析函数时一组内的数据是如何排序的.

10 FUNCTION子句

ORACLE提供了26个分析函数,按功能分5类
分析函数分类
等级(ranking)函数:用于寻找前N种查询
开窗(windowing)函数:用于计算不同的累计,如SUM,COUNT,AVG,MIN,MAX等,作用于数据的一个窗口上
例:
sum(t.sal) over (order by t.deptno,t.ename) running_total,
sum(t.sal) over (partition by t.deptno order by t.ename) department_total
制表(reporting)函数:与开窗函数同名,作用于一个分区或一组上的所有列
例:
sum(t.sal) over () running_total2,
sum(t.sal) over (partition by t.deptno ) department_total2
制表函数与开窗函数的关键不同之处在于OVER语句上缺少一个ORDER BY子句!
LAG,LEAD函数:这类函数允许在结果集中向前或向后检索值,为了避免数据的自连接,它们是非常用用的.
VAR_POP,VAR_SAMP,STDEV_POPE及线性的衰减函数:计算任何未排序分区的统计值

Oracle 11g的分析函数

AVG *

CORR *

COUNT *

COVAR_POP *

COVAR_SAMP *

CUME_DIST

DENSE_RANK

FIRST

FIRST_VALUE *

LAG

LAST

LAST_VALUE *

LEAD

LISTAGG

MAX *

MIN *

NTH_VALUE *

NTILE

PERCENT_RANK

PERCENTILE_CONT

PERCENTILE_DISC

RANK

RATIO_TO_REPORT

REGR_ (Linear Regression) Functions *

ROW_NUMBER

STDDEV *

STDDEV_POP *

STDDEV_SAMP *

SUM *

VAR_POP *

VAR_SAMP *

VARIANCE *

10.1.1 PARTITION子句

按照表达式分区(就是分组),如果省略了分区子句,则全部的结果集被看作是一个单一的组

10.1.2 ORDER BY子句

分析函数中ORDER BY的存在将添加一个默认的开窗子句,这意味着计算中所使用的行的集合是当前分区中当前行和前面所有行,没有ORDER BY,默认的窗口是全部的分区 在Order by 子句后可以添加nulls last,如:order by comm desc nulls last   表示排序时忽略comm列为空的行.  

10.1.3 WINDOWING子句

用于定义分析函数将在其上操作的行的集合
Windowing子句给出了一个定义变化或固定的数据窗口的方法,分析函数将对这些数据进行操作.默认的窗口是一个固定的窗口,仅仅在一组的第一行开始,一直继续到当前行,要使用窗口,必须使用ORDER BY子句.根据2个标准可以建立窗口:数据值的范围(RANGES)或与当前行的行偏移量.

5)Rang窗口
RANGE窗口仅对NUMBERS和DATES起作用,因为不可能从VARCHAR2中增加或减去N个单元
另外的限制是ORDER BY中只能有一列,因而范围实际上是一维的,不能在N维空间中

6)Row窗口
利用ROW分区,就没有RANGE分区那样的限制了,数据可以是任何类型,且ORDER BY 可以包括很多列

7)Specifying窗口
UNBOUNDED PRECEDING:这个窗口从当前分区的每一行开始,并结束于正在处理的当前行
CURRENT ROW:该窗口从当前行开始(并结束)
Numeric Expression PRECEDING:对该窗口从当前行之前的数字表达式(Numeric Expression)的行开始,对RANGE来说,从行序值小于数字表达式的当前行的值开始.
Numeric Expression FOLLOWING:该窗口在当前行Numeric Expression行之后的行终止(或开始),且从行序值大于当前行Numeric Expression行的范围开始(或终止)
rows between 100 preceding and 100 following:当前行100前,当前后100后

over(order by salary) 按照salary排序进行累计,order by是个默认的开窗函数

over(partition by deptno)按照部门分区

over(order by salary range between 50 preceding and 150 following)

每行对应的数据窗口是之前行幅度值不超过50,之后行幅度值不超过150 范围[current_value-50, current_value+150]

over(order by salary rows between 50 preceding and 150 following)

每行对应的数据窗口是之前50行,之后150行

over(order by salary rows between unbounded preceding and unbounded following)

每行对应的数据窗口是从第一行到最后一行,等效:

over(order by salary range between unbounded preceding and unbounded following)

注意:分析函数允许你对一个数据集进排序和筛选,这是SQL从来不能实现的.除了最后的Order by子句之外,分析函数是在查询中执行的最后的操作集,这样的话,就不能直接在谓词中使用分析函数,即不能在上面使用wherehaving子句!!!

10.2 排名

Oracle从8i开始就提供了3个排名函数:rand,dense_rank,row_number

Rank,Dense_rank,Row_number函数为每条记录产生一个从1开始至N的自然数,N的值可能小于等于记录的总数。这3个函数的唯一区别在于当碰到相同数据时的排名策略。
ROW_NUMBER

Row_number函数返回一个唯一的值,当碰到相同数据时,排名按照记录集中记录的顺序依次递增。

DENSE_RANK
Dense_rank函数返回一个唯一的值,除非当碰到相同数据时,此时所有相同数据的排名都是一样的。

RANK
Rank函数返回一个唯一的值,除非遇到相同的数据时,此时所有相同数据的排名是一样的,同时会在最后一条相同记录和下一条不同记录的排名之间空出排名。

SELECT department_id, last_name, salary,

RANK() OVER (PARTITION BY department_id ORDER BY salary) RANK,

DENSE_RANK() OVER (PARTITION BY department_id ORDER BY salary) DENSE_RANK,

ROW_NUMBER() OVER (PARTITION BY department_id ORDER BY salary) ROW_NUMBER

FROM employees WHERE department_id = 50

ORDER BY RANK, last_name;

DEPARTMENT_ID LAST_NAME SALARY RANK DENSE_RANK ROW_NUMBER

------------- --------------- ---------- ---------- ---------- ----------

50 Olson 2100 1 1 1

50 Markle 2200 2 2 2

50 Philtanker 2200 2 2 3

50 Gee 2400 4 3 4

50 Landry 2400 4 3 5

50 Marlow 2500 6 4 6

50 Vargas 2500 6 4 7

50 Sullivan 2500 6 4 8

50 Perkins 2500 6 4 9

50 Patel 2500 6 4 10

50 OConnell 2600 11 5 11

50 Grant 2600 11 5 12

50 Matos 2600 11 5 13

50 Seo 2700 14 6 14

50 Mikkilineni 2700 14 6 15

50 Geoni 2800 16 7 16

50 Atkinson 2800 16 7 17

50 Jones 2800 16 7 18

…….

请注意上面的绿色高亮部分,这里生动的演示了3种不同的排名策略:

Rank

Dense_rank

Row_number

不同值排名

1,2,3,4,…..

1,2,3,4,…..

1,2,3,4,…..

有相同值排名

1,2,2,4,4,…..

1,2,2,3,3,…..

1,2,3,4,5…..

存在断层

顺序递增

顺序递增

比较上面3种不同的策略,我们在选择的时候就要根据客户的需求来定夺了:
①假如只需要指定数目的记录,那么采用row_number是最简单的,但有漏掉的记录的危险
②假如需要所有达到排名水平的记录,那么采用rank或dense_rank是不错的选择。至于选择哪一种则看客户的需要,选择dense_rank或得到最大的记录

10.3 First/Last

排名查询

功能描述:从DENSE_RANK返回的集合中取出排在最前面的一个值的行(可能多行,因为值可能相等),因此完整的语法需要在开始处加上一个集合函数以从中取出记录
SAMPLE:下面例子中DENSE_RANK按部门分区,再按佣金commission_pct排序,FIRST取出佣金最低的对应的所有行,然后前面的MIN函数从这个集合中取出薪水最低的值;LAST取出佣金最高的对应的所有行,然后前面的MAX函数从这个集合中取出薪水最高的值

SELECT last_name, department_id, salary,

MIN(salary) KEEP (DENSE_RANK FIRST ORDER BY commission_pct)

OVER (PARTITION BY department_id) "Worst",

MAX(salary) KEEP (DENSE_RANK LAST ORDER BY commission_pct)

OVER (PARTITION BY department_id) "Best"

FROM employees

ORDER BY department_id, salary, last_name;

LAST_NAME DEPARTMENT_ID SALARY Worst Best

--------------- ------------- ---------- ---------- ----------

Whalen 10 4400 4400 4400

Fay 20 6000 6000 13000

Hartstein 20 13000 6000 13000

Colmenares 30 2500 2500 11000

Himuro 30 2600 2500 11000

Tobias 30 2800 2500 11000

Baida 30 2900 2500 11000

Khoo 30 3100 2500 11000

Raphaely 30 11000 2500 11000

Mavris 40 6500 6500 6500

Olson 50 2100 2100 8200

Markle 50 2200 2100 8200

Philtanker 50 2200 2100 8200

10.4 ntile

将列值分为几个等级。

HR@test>SELECT last_name, salary, NTILE(4) OVER (ORDER BY salary DESC) AS quartile

2 FROM employees

3 WHERE department_id = 100

4 ORDER BY quartile;

LAST_NAME SALARY QUARTILE

--------------- ---------- ----------

Greenberg 12008 1

Faviet 9000 1

Chen 8200 2

Urman 7800 2

Sciarra 7700 3

Popp 6900 4

10.5 first_value/last_value:

功能描述:返回组中数据窗口的第一个值。
SAMPLE:下面例子计算80部门分区按薪水排序的数据窗口的第一个值对应的名字,如果薪水的第一个值有多个,则从多个对应的名字中取缺省排序的第一个名字

SELECT department_id, last_name, salary,

FIRST_VALUE(last_name) OVER (ORDER BY salary ROWS UNBOUNDED PRECEDING) AS lowest_sal,last_VALUE(last_name) OVER (ORDER BY salary range between unbounded preceding and unbounded following) AS great_sal

FROM (SELECT * FROM employees

WHERE department_id = 80

ORDER BY employee_id)

ORDER BY salary;

DEPARTMENT_ID LAST_NAME SALARY LOWEST_SAL GREAT_SAL

------------- --------------- ---------- -------------------------------------------------- --------------------------------------------------

80 Kumar 6100 Kumar Russell

80 Banda 6200 Kumar Russell

80 Johnson 6200 Kumar Russell

80 Ande 6400 Kumar Russell

80 Lee 6800 Kumar Russell

…….

80 Russell 14000 Kumar Russell

10.6 lag、lead

功能描述:可以访问结果集中的其它行而不用进行自连接。它允许去处理游标,就好像游标是一个数组一样。在给定组中可参考当前行之前的行,这样就可以从组中与当前行一起选择以前的行。Offset是一个正整数,其默认值为1,若索引超出窗口的范围,就返回默认值(默认返回的是组中第一行),其相反的函数是LEAD

HR@test>select first_name,last_name,hire_date, lag(hire_date,1,'1987-01-01') over(order by hire_date) as prev_hire_date,hire_date-lag(hire_date,1,'1987-01-01') over(order by hire_date) as days_between_hires from hr.employees order by hire_date;

FIRST_NAME LAST_NAME HIRE_DATE PREV_HIRE_ DAYS_BETWEEN_HIRES

---------------------------------------- --------------- ---------- ---------- ------------------

Lex De Haan 2001-01-13 1987-01-01 5126

Susan Mavris 2002-06-07 2001-01-13 510

Hermann Baer 2002-06-07 2002-06-07 0

Shelley Higgins 2002-06-07 2002-06-07 0

William Gietz 2002-06-07 2002-06-07 0

Daniel Faviet 2002-08-16 2002-06-07 70

Nancy Greenberg 2002-08-17 2002-08-16 1

Den Raphaely 2002-12-07 2002-08-17 112

Payam Kaufling 2003-05-01 2002-12-07 145

Alexander Khoo 2003-05-18 2003-05-01 17

Steven King 2003-06-17 2003-05-18 30

Renske Ladwig 2003-07-14 2003-06-17 27

Jennifer Whalen 2003-09-17 2003-07-14 65

10.7 RATIO_TO_REPORT

HR@test>HR@test>SELECT last_name, salary, RATIO_TO_REPORT(salary) OVER () AS rr

2 FROM employees

3 WHERE job_id = 'PU_CLERK'

4 ORDER BY last_name, salary, rr;

LAST_NAME SALARY RR

--------------- ---------- ----------

Baida 2900 .208633094

Colmenares 2500 .179856115

Himuro 2600 .18705036

Khoo 3100 .223021583

Tobias 2800 .201438849

10.8 AVG /count/sum

功能描述:用于计算一个组和数据窗口内表达式的平均值。
SAMPLE:下面的例子中列c_mavg计算员工表中每个员工的平均薪水报告,该平均值由当前员工和与之具有相同经理的前一个和后一个三者的平均数得来;

OE@test>OE@test>SELECT manager_id, last_name, hire_date, salary,

2 AVG(salary) OVER (PARTITION BY manager_id ORDER BY hire_date

3 ROWS BETWEEN 1 PRECEDING AND 1 FOLLOWING) AS c_mavg

4 FROM employees;

MANAGER_ID LAST_NAME HIRE_DATE SALARY C_MAVG

---------- --------------- ----------------------- ---------- ----------

100 De Haan 13-JAN-2001 00:00:00 17000 14000

100 Raphaely 07-DEC-2002 00:00:00 11000 11966.6667

100 Kaufling 01-MAY-2003 00:00:00 7900 10633.3333

100 Hartstein 17-FEB-2004 00:00:00 13000 9633.33333

100 Weiss 18-JUL-2004 00:00:00 8000 11666.6667

100 Russell 01-OCT-2004 00:00:00 14000 11833.3333

100 Partners 05-JAN-2005 00:00:00 13500 13166.6667

100 Errazuriz 10-MAR-2005 00:00:00 12000 11233.3333

100 Fripp 10-APR-2005 00:00:00 8200 12400

100 Kochhar 21-SEP-2005 00:00:00 17000 10566.6667

100 Vollman 10-OCT-2005 00:00:00 6500 11500

100 Cambrault 15-OCT-2007 00:00:00 11000 7766.66667

100 Mourgos 16-NOV-2007 00:00:00 5800 9100

100 Zlotkey 29-JAN-2008 00:00:00 10500 8150

101 Baer 07-JUN-2002 00:00:00 10000 11004

101 Higgins 07-JUN-2002 00:00:00 12008 9502.66667

SAMPLE:下面例子中计算每个员工在按薪水排序中当前行附近薪水在[n-50,n+150]之间的行数,n表示当前行的薪水
例如,Philtanker的薪水2200,排在他之前的行中薪水大于等于2200-50的有1行,排在他之后的行中薪水小于等于2200+150的行没有,所以count计数值cnt3为2(包括自己当前行);cnt2值相当于小于等于当前行的SALARY值的所有行数

OE@test>SELECT last_name, salary, COUNT(*) OVER () AS cnt1,COUNT(*) OVER (ORDER BY salary) AS cnt2,COUNT(*) OVER (ORDER BY salary RANGE BETWEEN 50 PRECEDING AND 150 FOLLOWING) AS cnt3 FROM employees;

LAST_NAME SALARY CNT1 CNT2 CNT3

--------------- ---------- ---------- ---------- ----------

Olson 2100 107 1 3

Philtanker 2200 107 3 2

Markle 2200 107 3 2

Landry 2400 107 5 8

Gee 2400 107 5 8

Perkins 2500 107 11 10

Colmenares 2500 107 11 10

Patel 2500 107 11 10

Vargas 2500 107 11 10

Sullivan 2500 107 11 10

Marlow 2500 107 11 10

OConnell 2600 107 15 6

Grant 2600 107 15 6

Himuro 2600 107 15 6

Matos 2600 107 15 6

Mikkilineni 2700 107 17 6

Seo 2700 107 17 6

Tobias 2800 107 21 7

Geoni 2800 107 21 7

Atkinson 2800 107 21 7

Jones 2800 107 21 7

Baida 2900 107 24 5

11 其它问题
12 null排序的处理

SCOTT@test>select empno,ename,mgr,sal,comm from emp order by comm desc nulls last;

EMPNO ENAME MGR SAL COMM

---------- -------------------- ---------- ---------- ----------

7654 MARTIN 7698 1250 1400

7521 WARD 7698 1250 500

7499 ALLEN 7698 1600 300

7844 TURNER 7698 1500 0

7788 SCOTT 7566 3000

7839 KING 1000

7876 ADAMS 7788 1100

7900 JAMES 7698 950

7902 FORD 7566 3000

7934 MILLER 7782 1000

7698 BLAKE 7839 2850

7566 JONES 7839 2975

7369 SMITH 7902 800

7782 CLARK 7839 1000

SCOTT@test>select empno,ename,mgr,sal,comm from emp order by comm; ---默认

EMPNO ENAME MGR SAL COMM

---------- -------------------- ---------- ---------- ----------

7844 TURNER 7698 1500 0

7499 ALLEN 7698 1600 300

7521 WARD 7698 1250 500

7654 MARTIN 7698 1250 1400

7788 SCOTT 7566 3000

7839 KING 1000

7876 ADAMS 7788 1100

7900 JAMES 7698 950

7902 FORD 7566 3000

7934 MILLER 7782 1000

7698 BLAKE 7839 2850

7566 JONES 7839 2975

7369 SMITH 7902 800

7782 CLARK 7839 1000

12.1.1 count中null 的处理

count(*)null值在内所有行

count(comssion_pct) 不包括null值

OE@test>select count(*),count(commission_pct),avg(commission_pct),sum(commission_pct)/count(commission_pct) from hr.employees;

COUNT(*) COUNT(COMMISSION_PCT) AVG(COMMISSION_PCT) SUM(COMMISSION_PCT)/COUNT(COMMISSION_PCT)

---------- --------------------- ------------------- -----------------------------------------

107 35 .222857143 .222857143

13 LISTAGG

LISTAGG(measure_expr [, 'delimiter']) WITHIN GROUP (order_by_clause) [OVER query_partition_clause]

按照order by 的排序,顺序连接measure_expr列的值,delimiter 缺省为null

HR@test>SELECT LISTAGG(last_name, '; ')

2 WITHIN GROUP (ORDER BY hire_date, last_name) "Emp_list",

3 MIN(hire_date) "Earliest"

4 FROM employees

5 WHERE department_id = 30;

Emp_list Earliest

--------------------------------------------------------------------------------------- -----------------------

Raphaely; Khoo; Tobias; Baida; Himuro; Colmenares 07-DEC-2002 00:00:00

HR@test>SELECT hire_date, last_name

2 FROM employees

3 WHERE department_id = 30 order by hire_date, last_name;

HIRE_DATE LAST_NAME

----------------------- --------------------------------------------------

07-DEC-2002 00:00:00 Raphaely

18-MAY-2003 00:00:00 Khoo

24-JUL-2005 00:00:00 Tobias

24-DEC-2005 00:00:00 Baida

15-NOV-2006 00:00:00 Himuro

10-AUG-2007 00:00:00 Colmenares

分组

HR@test>SELECT department_id "Dept.",

2 LISTAGG(last_name, '; ') WITHIN GROUP (ORDER BY hire_date) "Employees"

3 FROM employees

4 GROUP BY department_id

5 ORDER BY department_id;

Dept. Employees

---------- --------------------------------------------------

10 Whalen

20 Hartstein; Fay

30 Raphaely; Khoo; Tobias; Baida; Himuro; Colmenares

40 Mavris

50 Kaufling; Ladwig; Rajs; Sarchand; Bell; Mallin; We

iss; Davies; Marlow; Bull; Everett; Fripp; Chung;

Nayer; Dilly; Bissot; Vollman; Stiles; Atkinson; T

aylor; Seo; Fleaur; Matos; Patel; Walsh; Feeney; D

ellinger; McCain; Vargas; Gates; Rogers; Mikkiline

ni; Landry; Cabrio; Jones; Olson; OConnell; Sulliv

an; Mourgos; Gee; Perkins; Grant; Geoni; Philtanke

r; Markle

60 Austin; Hunold; Pataballa; Lorentz; Ernst

70 Baer

80 King; Sully; Abel; McEwen; Russell; Partners; Tuck

er; Errazuriz; Smith; Ozer; Hutton; Bernstein; Hal

l; Vishney; Doran; Fox; Bloom; Taylor; Olsen; Livi

ngston; Sewall; Cambrault; SMITH; Greene; Bates; C

ambrault; Tuvault; Johnson; Marvins; Zlotkey; Lee;

Ande; Banda; Kumar

90 De Haan; King; Kochhar

100 Faviet; Greenberg; Chen; Sciarra; Urman; Popp

110 Gietz; Higgins

Grant

SELECT department_id "Dept", hire_date "Date", last_name "Name",

LISTAGG(last_name, '; ') WITHIN GROUP (ORDER BY hire_date, last_name)

OVER (PARTITION BY department_id) as "Emp_list"

FROM employees

ORDER BY "Dept", "Date", "Name";

Dept Date Name Emp_list

---------- ----------------------- -------------------- --------------------------------------------------

10 17-SEP-2003 00:00:00 Whalen Whalen

20 17-FEB-2004 00:00:00 Hartstein Hartstein; Fay

20 17-AUG-2005 00:00:00 Fay Hartstein; Fay

30 07-DEC-2002 00:00:00 Raphaely Raphaely; Khoo; Tobias; Baida; Himuro; Colmenares

30 18-MAY-2003 00:00:00 Khoo Raphaely; Khoo; Tobias; Baida; Himuro; Colmenares

30 24-JUL-2005 00:00:00 Tobias Raphaely; Khoo; Tobias; Baida; Himuro; Colmenares

30 24-DEC-2005 00:00:00 Baida Raphaely; Khoo; Tobias; Baida; Himuro; Colmenares

30 15-NOV-2006 00:00:00 Himuro Raphaely; Khoo; Tobias; Baida; Himuro; Colmenares

30 10-AUG-2007 00:00:00 Colmenares Raphaely; Khoo; Tobias; Baida; Himuro; Colmenares

40 07-JUN-2002 00:00:00 Mavris Mavris

……

14 行列转换
14.1 Pivot

行转列

OE@test>select customer_id,product_id,quantity from orders join order_items using(order_id) where product_id in (3170 ,3176 ,3182,3163 ,3165 ) ; ---五个产品的销售情况

CUSTOMER_ID PRODUCT_ID QUANTITY

----------- ---------- ----------

101 3163 142

101 3163 66

104 3182 77

104 3176 72

104 3170 70

104 3165 64

104 3163 61

106 3176 62

106 3163 55

107 3165 76

108 3163 45

108 3165 31

109 3182 115

109 3165 112

116 3165 10

116 3163 5

116 3176 24

116 3170 24

116 3170 24

117 3165 67

117 3163 63

118 3170 42

119 3170 36

求这五个产品中每个客户购买情况。

with order_item_query as (select customer_id,product_id,quantity from orders join order_items using(order_id)) select * from oe.order_item_query pivot ( sum(quantity) as sum_qty for (product_id) in(3170 as P3170,3176 as P3176,3182 as P3182,3163 as P3163,3165 as P3165)) order by customer_id;

CUSTOMER_ID P3170_SUM_QTY P3176_SUM_QTY P3182_SUM_QTY P3163_SUM_QTY P3165_SUM_QTY

----------- ------------- ------------- ------------- ------------- -------------

101 208

102

103

104 70 72 77 61 64

105

106 62 55

107 76

108 45 31

109 115 112

116 48 24 5 10

117 63 67

14.2 Unpivot

–列转行

OE@test>select * from email_signup;

USER_ACCOUNT SIGNUP_DATE USER_EMAIL FRIEND1_EMAIL FRIEND2_EMAIL FRIEND3_EMAIL

-------------------- ----------------------- --------------- --------------- --------------- ---------------

lakala 18-MAR-2014 00:00:00 123@lakala.com 1@lakala.com 2@lakala.com 3@lakala.com

lkl 17-MAR-2014 00:00:00 p123@lakala.com p1@lakala.com p2@lakala.com p3@lakala.com

OE@test>select user_account, signup_date, src_col_name, friend_email

2 from email_signup

3 unpivot (

4 (friend_email) for src_col_name

5 in (user_email, friend1_email, friend2_email, friend3_email)

6 )

7 ;

USER_ACCOUNT SIGNUP_DATE SRC_COL_NAME FRIEND_EMAIL

-------------------- ----------------------- -------------------------- --------------------

lakala 18-MAR-2014 00:00:00 USER_EMAIL 123@lakala.com

lakala 18-MAR-2014 00:00:00 FRIEND1_EMAIL 1@lakala.com

lakala 18-MAR-2014 00:00:00 FRIEND2_EMAIL 2@lakala.com

lakala 18-MAR-2014 00:00:00 FRIEND3_EMAIL 3@lakala.com

lkl 17-MAR-2014 00:00:00 USER_EMAIL p123@lakala.com

lkl 17-MAR-2014 00:00:00 FRIEND1_EMAIL p1@lakala.com

lkl 17-MAR-2014 00:00:00 FRIEND2_EMAIL p2@lakala.com

lkl 17-MAR-2014 00:00:00 FRIEND3_EMAIL p3@lakala.com

原文地址:https://www.cnblogs.com/afx1007/p/4061810.html