(Problem 10)Summation of primes

The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17.

Find the sum of all the primes below two million.

#include<stdio.h>
#include<math.h>
#include<stdbool.h>

#define N 2000000

bool prim(int n)
{
    int i;
    for(i=2; i*i<=n; i++)
    {
        if(n%i==0)
            return false;
    }
    return true;
}

int main()
{
    int i;
    long long sum=2;
    for(i=3; i<=N; i=i+2)
    {
        if(prim(i))
        {
            sum+=i;
        }
    }
    printf("%lld
",sum);

    return 0;
}
Answer:
142913828922
原文地址:https://www.cnblogs.com/acutus/p/3544791.html