(Problem 4)Largest palindrome product

A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 × 99.

Find the largest palindrome made from the product of two 3-digit numbers.

#include<stdio.h>
#include<math.h>
#include<string.h>
#include<ctype.h>
#include<stdlib.h>
#include<stdbool.h>


bool palindromic(int n)  //判断一个整数是否为回文数
{
    char s[10];
    sprintf(s,"%d",n);  //将整数n保存在字符数组s中
    int i,len;
    len=strlen(s);
    for(i=0; i<len/2; i++)
    {
        if(s[i]!=s[len-i-1])
            return false;
    }
    return true;
}

bool have_the_factor(int n)   //判断是否含有两个3位数的因数
{
    int s=999;
    int r,b;
    while(s>100)
    {
        if((n%s)==0 && ((n/s)>100  && (n/s)<1000))
            return true;
        s--;
    }
    return false;
}

int main()
{
    int i=1000000;
    while(i>0)
    {
        if(palindromic(i) && have_the_factor(i))
        {
            printf("%d
",i);
            break;
        }
        i--;
    }
    return 0;
}
Answer:
906609
原文地址:https://www.cnblogs.com/acutus/p/3544367.html