ACM_Repeating Characters

Repeating Characters

Time Limit: 2000/1000ms (Java/Others)

Problem Description:

For this problem, you will write a program that takes a string of characters, S, and creates a new string of characters, T, with each character repaeated R times. That is, R copies of the first character of S, followed by R copies of the second character of S, and so on. Valid characters for S are the QR Code "alphanumeric" characters:
  
0 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z $ % * + - . / : 

Input:

The first line of input contains a single integer P,(1 <= P <= 1000), which is the number of data sets that follow. Each data set is a single ling of input consisting of the data set number N, followed by a space, followed by the repeat count R, (1 <= R <= 8), followed by a space , followed by the string S. The length of string S will always be at least one and no more than 20 characters. All the characters will be from the set of characters shown above.

Output:

For each data set there is one ling of output. It contains the data set number, N, followed by a single space which is then followed by the new string T, which is made of each character in S repeated R times.

Sample Input:

2
1 3 ABC
2 5 /HTP

Sample Output:

1 AAABBBCCC
2 /////HHHHHTTTTTTPPPPP
解题思路：将每个字符输出r次即可，水过！
AC代码：

#include<bits/stdc++.h>
using namespace std;
int main(){
    int p,t,r,k;char tmp[25],str[200];
    while(cin>>p){
        for(int i=1;i<=p;++i){
            memset(str,'',sizeof(str));
            cin>>t>>r>>tmp;k=0;
            for(int j=0;tmp[j]!='';++j)
                for(int g=1;g<=r;++g)//每次填充r个相同的字符
                    str[k++]=tmp[j];
            cout<<t<<' '<<str<<endl;
        }
    }
    return 0;
}