从SQL Server数据库提取图片并显示在DataGrid
<!-- ReadImage.aspx -->
<%
@ Page Language="vb" %>
<%@ Import Namespace="System.Data" %>
<%@ Import Namespace="System.Data.SqlClient" %>
<HTML>
<HEAD>
<script runat=server>
Public Sub Page_Load(sender As Object, e As EventArgs)
Dim strImageID as String = Request.QueryString("id")
Dim myConnection As New SqlConnection("Data Source=.;Initial Catalog=mxh;User Id=sa;Password=;")
Dim myCommand As New SqlCommand("Select PersonImageType, PersonImage from Person Where PersonID=" _
+ strImageID, myConnection)
Try
myConnection.Open()
Dim myDataReader as SqlDataReader
myDataReader = myCommand.ExecuteReader(CommandBehavior.CloseConnection)
Do While (myDataReader.Read())
Response.ContentType = myDataReader.Item("PersonImageType")
Response.BinaryWrite(myDataReader.Item("PersonImage"))
Loop
myConnection.Close()
Catch SQLexc As SqlException
End Try
End Sub
</script>
</HEAD>
<body>
<form runat="server" ID="Form1"></form>
</body>
</HTML>
<!-- DataGridShowImage.aspx -->
<%@ Page Language="vb" %>
<%@ Import Namespace="System.Data" %>
<%@ Import Namespace="System.Data.SqlClient" %>
<html>
<head>
<title>用户列表</title>
<script runat=server>
Sub Page_Load(sender As Object, e As EventArgs)
If Not Page.IsPostBack Then
BindGrid()
End If
End Sub
Private Sub BindGrid()
Dim strCnn As String = "Data Source=.;Initial Catalog=mxh;User Id=sa;Password=;"
Dim myConnection As SqlConnection = New SqlConnection(strCnn)
Dim myCommand As SqlCommand = New SqlCommand("SELECT * FROM Person", myConnection)
myCommand.CommandType = CommandType.Text
Try
myConnection.Open()
DG_Persons.DataSource = myCommand.ExecuteReader(CommandBehavior.CloseConnection)
DG_Persons.DataBind()
Catch SQLexc As SqlException
Response.Write("Error occured while Generating Data. Error is " & SQLexc.ToString())
End Try
End Sub
Function FormatURL(strArgument) as String
Return ("ReadImage.aspx?id=" & strArgument)
End Function
</script>
</head>
<body style="font: 9pt 宋体">
<h3 align=center>从数据库中取得照片并显示在DataGrid中</h3>
<form id="Form1" method="post" runat="server">
<asp:DataGrid ID="DG_Persons" AutoGenerateColumns=False Width="99%"
HeaderStyle-BackColor="#ff0000" HeaderStyle-Font-Bold="True" HeaderStyle-ForeColor="#ffffff"
ItemStyle-BackColor=Beige BorderColor="#000000" Runat=server HeaderStyle-HorizontalAlign=Center>
<Columns>
<asp:TemplateColumn HeaderText="姓名">
<ItemTemplate>
<asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonName") %>' ID="Label1"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="电子邮件">
<ItemTemplate>
<asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonEmail") %>' ID="Label2"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="性别">
<ItemTemplate>
<asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonSex") %>' ID="Label3"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="出生日期">
<ItemTemplate>
<asp:Label Runat="server"
Text='<%# DataBinder.Eval(Container.DataItem, "PersonDOB") %>' ID="Label4"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="照片">
<ItemTemplate>
<asp:Image Runat=server ID="Image1" Width="150" Height="125"
ImageUrl='<%# FormatURL(DataBinder.Eval(Container.DataItem, "PersonID")) %>' />
</ItemTemplate>
</asp:TemplateColumn>
</Columns>
</asp:DataGrid>
</form>
</body>
</html>
原文地址：https://www.cnblogs.com/acelove/p/86292.html