[C puzzle book] operators

#include <stdio.h>

int main(void)
{
    int x;
    x = -3 + 4 * 5 -6; printf("%d\n",x);
    x = 3 + 4 % 5 - 6; printf("%d\n",x); //How to get it?
    x = -3 * 4 % - 6 / 5; printf("%d\n",x);
    x = (7 + 6) % 5 / 2; printf("%d\n",x);


}

 1 #include <stdio.h>
 2 #define PRINT(int) printf("%d\n",int)
 3 
 4 int main(void)
 5 {
 6     int x,y,z;
 7     x=2; y=1; z=0;
 8     x=x&&y||z; PRINT(x);
 9     PRINT(x|| !y && z);
10     x = y =1;
11     z =x++ -1; PRINT(x); PRINT(z);
12     z += -x++ + ++y; PRINT(x); PRINT(z);
13     z = x / ++ x; PRINT(z);
14 
15 
16 }

#include <stdio.h>
#define PRINT(int) printf("int = %d\n",int)

int main(void)
{
    int x, y, z;
    x = 03; y = 02; z = 01;
    PRINT(x | y & z);
    PRINT(x | y & -z);
    PRINT(x ^ y & -z);
    PRINT(x & y && z);

    x=1; y = -1;
    PRINT(! x | x);
    PRINT(~ x | x);
    PRINT(x ^ x);
    x <<= 3; PRINT(x);
    y <<= 3; PRINT(y);
    y >>= 3; PRINT(y);

}

 1 #include <stdio.h>
 2 //#define PRINT(int) printf("int = %d\n",int)
 3 #define PRINT(int) printf(#int" = %d\n",int)
 4 //Why add the # to get the right answer????
 5 int main(void)
 6 {
 7     int x =1, y = 1, z = 1;
 8     x += y += z;
 9     PRINT(x<y? y : x);
10     PRINT(x < y ? x++ : y++);
11     PRINT(x); PRINT(y);
12     PRINT(z += x <y? x++ : y++);
13     PRINT(y); PRINT(z);
14     x=3; y=z=4;
15     PRINT((z >= y >= x) ? 1 : 0);
16     PRINT( z >= y && y>= x);
17 }

 1 #include <stdio.h>
 2 #define PRINT3(x,y,z) printf("x=%d\ty=%d\tz=%d\n",x,y,z)
 3 
 4 int main(void)
 5 {
 6     int x, y, z;
 7     x = y = z =1 ;
 8     ++x || ++y && ++z; PRINT3(x,y,z);
 9     x = y = z =1 ;
10     ++x && ++y || ++z; PRINT3(x,y,z);
11     x = y = z =1 ;
12     ++x && ++y && ++z; PRINT3(x,y,z);
13     x = y = z = -1 ;
14     ++x && ++y || ++z; PRINT3(x,y,z);
15     x = y = z = -1 ;
16     ++x || ++y && ++z; PRINT3(x,y,z);
17     x = y = z = -1 ;
18     ++x && ++y && ++z; PRINT3(x,y,z);
19 
20 }