创建多线程Thread

创建一个线程：

# 方式一
from threading import Thread
import time


def func(n):
    time.sleep(1)
    print(n)


t = Thread(target=func, args=(1,))
t.start()

# 方式二
from threading import Thread
import time


class MyThread(Thread):
    def __init__(self,n):
        super().__init__()
        self.n = n
        
    def run(self):
        time.sleep(1)
        print(self.n)


t = MyThread(1)
t.start()

创建多线程：

from threading import Thread
import time


class MyThread(Thread):
    def __init__(self,n):
        super().__init__()
        self.n = n

    def run(self):
        time.sleep(1)
        print(self.n)


for i in range(10):
    t = MyThread(i)
    t.start()

from threading import Thread
import time


def func(n):
    time.sleep(1)
    print(n)


for i in range(10):
    t = Thread(target=func, args=(i,))
    t.start()

 一个进程中的线程数据是共享的：

from threading import Thread
import os


def func(args):
    global n
    n = 0
    print(n, os.getpid())


n = 100
t_list = []
for i in range(10):
    t = Thread(target=func, args=(i,))
    t.start()
    t_list.append(t)
for t in t_list:
    t.join()
print(n)

另一种情况：

from threading import Thread
import os,time


def func(args):

    global n
    n = args
    time.sleep(0.1)
    print(n, os.getpid())



n = 100
t_list = []
for i in range(10):
    t = Thread(target=func, args=(i,))
    t.start()
    t_list.append(t)
for t in t_list:
    t.join()
print(n)

看到结果都变成一样的了，因为每个线程都将n的值变一次，不管变几次，n最终只有一个值，所在在0.1秒之后在输出n，都输出n的值了，就变成一样的了。

 这种情况就会导致数据不安全，因为我不想要同一个输出结果，我想每个线程更改数据都要输出结果，加锁就可以了。

如下：

from threading import Thread, Lock
import os,time


def func(args, lock):
    lock.acquire()
    global n
    n = args
    time.sleep(0.1)
    print(n, os.getpid())
    lock.release()

lock = Lock()
n = 100
t_list = []
for i in range(1000):
    t = Thread(target=func, args=(i, lock))
    t2 = Thread(target=func, args=(i, lock))
    t.start()
    t2.start()
    t_list.append(t)
    t_list.append(t2)
for t in t_list:
    t.join()
print(n)

这样每个线程的结果都不一样了。

多线程的效率问题：

from threading import Thread
import time
from multiprocessing import Process


def func(n):
    n += 1


if __name__ == "__main__":
    t1 = time.time()
    t_list = []
    for i in range(50):
        t = Thread(target=func, args=(i,))
        t.start()
        t_list.append(t)
    for t in t_list:
        t.join()
    t2 = time.time() - t1

    t3 = time.time()
    p_list = []
    for i in range(50):
        p = Process(target=func, args=(i,))
        p.start()
        p_list.append(p)
    for p in p_list:
        p.join()
    t4 = time.time() - t3

    print(t2, t4)

打印结果：

0.007979869842529297 3.0359175205230713

起50个线程的时间远比起50个进程的时间短。