/*
从键盘输入一个日期，格式为 yyyy-M-d
要求计算该日期与 1949 年 10 月 1 日距离多少天
例如：
用户输入了：1949-10-2
程序输出：1
用户输入了：1949-11-1
程序输出：31
*/
package Question20_29;
import java.util.Scanner;
public class Question24MustRemember {
public static int dayOfYear[]={365,366};//平年365天,闰年366天
public static int dayOfMonth[][]={
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{0,31,28,31,30,31,30,31,31,30,31,30,31},
{0,31,29,31,30,31,30,31,31,30,31,30,31}
};
public static int dayOfYearIndex(int year){ //根据是否是闰年来给出dayOfYear的数组的下标
if((year%4==0&&year%100!=0)||year%400==0){
return 1;
}
return 0;
}
public static int dayApartFromTheBrginOfYear(int year,int month,int day){//计算month月day日是year年的第
几天
int days=day;
for (int i = 1; i < month; i++) {
days+=dayOfMonth[dayOfYearIndex(year)][i];
}
return days;
}
public static int apartDays(String startDayString,String endDayString ) {
String s1[]=startDayString.split("-");
String s2[]=endDayString.split("-");
int days=0;
int flag;
int startYear=Integer.parseInt(s1[0]);
int endYear=Integer.parseInt(s2[0]);
int startMonth=Integer.parseInt(s1[1]);
int endMonth=Integer.parseInt(s2[1]);
int startDay=Integer.parseInt(s1[2]);
int endDay=Integer.parseInt(s2[2]);
for (int i = startYear; i < endYear; i++) {
days+=dayOfYear[dayOfYearIndex(i)];
}
days+=dayApartFromTheBrginOfYear(endYear,endMonth,endDay);
days-=dayApartFromTheBrginOfYear(startYear,startMonth,startDay);
return days;
}
public static void main(String[] args) {
Scanner scanner=new Scanner(System.in);
String startDayString="1949-10-01";
String endDayString=scanner.nextLine();
System.out.println(apartDays(startDayString, endDayString));
}
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}
运行结果：
输入日期格式为:(1949-10-2)
输入第一个日期:1949-10-2
输入第二个日期:1949-11-2
1949-10-2 到 1949-11-2
距离 31 天