[LeetCode] Anagrams

Given an array of strings, return all groups of strings that are anagrams.

Note: All inputs will be in lower-case.

用map记录出现的string的下标,避免了再次遍历。

class Solution {
public:
    vector<string> anagrams(vector<string> &strs) {
        vector<string> result;
        int len = strs.size();
        map<string,int> strIndex;//key是string,value是对应在strs中的下标
        for(int i=0;i<len;i++){
            string s0 = strs[i];
            sort(s0.begin(),s0.end());
            if(strIndex.count(s0)==0)
                strIndex[s0] = i;
            else{
                if(find(result.begin(),result.end(),strs[strIndex[s0]])==result.end())
                    result.push_back(strs[strIndex[s0]]);
                result.push_back(strs[i]);
            }
        
        }//end for
        return result;
    }//end func
};
原文地址:https://www.cnblogs.com/Xylophone/p/3926954.html