[LeetCode] Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, Given s = "Hello World", return 5.

class Solution {
public:
    int lengthOfLastWord(const char *s) {
        int len = strlen(s);
        if(len == 0)
            return 0;
        int i = len-1;
        int LastEnd = len-1;
        int LastStart = 0;

            while(s[i]==' '&& i>=0)
            {
               i--;
            }
            LastEnd = i;
            if(LastEnd == -1)
                return 0;
            while(s[i]!=' '&& i>=0)
            {
              i--;
            }
            LastStart = (i+1);
        
    
        return LastEnd-LastStart+1;
    }
};
原文地址:https://www.cnblogs.com/Xylophone/p/3848374.html