主要是把图形分析清楚，把循环理清楚就好。这里我是用了二维数组把图存下来，全都初始化为点号，然后通过循环来更改某些部分为$，最后输出二维数组。
1 #include<iostream> 2 #include<cstring> 3 4 using namespace std; 5 6 char num[130][130]; 7 8 void tu(int n) 9 { 10 int cont=n; 11 int j=1; 12 int row=9+(n-1)*4; 13 for(int i = 3; i <= row/2+1; i=i+2) 14 { 15 num[j][i]=num[j+1][i]=num[j+2][i]='$'; 16 num[j][row-i+1]=num[j+1][row-i+1]=num[j+2][row-i+1]='$'; 17 num[row-j+1][i]=num[row-j][i]=num[row-j-1][i]='$'; 18 num[row-j+1][row-i+1]=num[row-j][row-i+1]=num[row-j-1][row-i+1]='$'; 19 20 num[j+2][i-1]=num[j+2][i-2]='$'; 21 num[j+2][row-i+2]=num[j+2][row-i+3]='$'; 22 num[row-j-1][i-1]=num[row-j-1][i-2]='$'; 23 num[row-j-1][row-i+2]=num[row-j-1][row-i+3]='$'; 24 25 int temp=i+1; 26 while(temp<=row/2+1) 27 { 28 num[j][temp]=num[j][row-temp+1]=num[row-j+1][temp]=num[row-j+1][row-temp+1]='$'; 29 temp++; 30 } 31 j+=2; 32 temp=j; 33 while(temp<=row/2+1) 34 { 35 num[temp][i-2]=num[temp][row-i+3]=num[row-temp+1][i-2]=num[row-temp+1][row-i+3]='$'; 36 temp++; 37 } 38 } 39 for(int i = 1; i <= row;i++) 40 { 41 for(int j = 1; j <= row; j++) 42 cout<<num[i][j]; 43 cout<<endl; 44 } 45 46 } 47 int main() 48 { 49 int n; 50 while(cin>>n) 51 { 52 memset(num,'.',sizeof(num)); 53 tu(n); 54 } 55 return 0; 56 }