HDOJ1250 大数斐波那契问题[大数加法]

Hat's Fibonacci

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 3554    Accepted Submission(s): 1208


Problem Description
A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1.
F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4)
Your task is to take a number as input, and print that Fibonacci number.
 
Input
Each line will contain an integers. Process to end of file.
 
Output
For each case, output the result in a line.
 
Sample Input
100
 
Sample Output
4203968145672990846840663646 Note: No generated Fibonacci number in excess of 2005 digits will be in the test data, ie. F(20) = 66526 has 5 digits.
 
Author
戴帽子的
 
Recommend
Ignatius.L
 
 
code:
 
 1 import java.util.*;
 2 import java.math.*;
 3 public class Main
 4 {
 5     public static void main(String []args)
 6     {
 7         int n,i;        
 8         Scanner cin=new Scanner(System.in);
 9         while(cin.hasNext())
10         {
11             n=cin.nextInt();
12             BigInteger a=BigInteger.valueOf(1);
13               BigInteger b=BigInteger.valueOf(1);
14             BigInteger c=BigInteger.valueOf(1);
15             BigInteger d=BigInteger.valueOf(1);
16             BigInteger e=BigInteger.valueOf(1);
17             for(i=5;i<=n;i++)
18             {
19                 e=a.add(b.add(c.add(d)));
20                 a=b;
21                 b=c;
22                  c=d;
23                 d=e;         
24             }
25             System.out.println(e);    
26         }
27     }
28 }






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Brad(Bowen) Xu
E-Mail : maxxbw1992@gmail.com


原文地址:https://www.cnblogs.com/XBWer/p/2560567.html