The Bells are Ringing UVALive

输出整数N,使得  t1 <= N  统计有多少组t1,t2,t3,满足:1<t1<t2<t3<=1000000,t3-t1<=25,且t1,t2,t3的最小公倍数是N

枚举t1就好了

#include <iostream>
#include <cstdio>
#include <sstream>
#include <cstring>
#include <map>
#include <set>
#include <vector>
#include <stack>
#include <queue>
#include <algorithm>
#include <cmath>
#define MOD 2018
#define LL long long
#define ULL unsigned long long
#define Pair pair<int, int>
#define mem(a, b) memset(a, b, sizeof(a))
#define _  ios_base::sync_with_stdio(0),cin.tie(0)
//freopen("1.txt", "r", stdin);
using namespace std;
const int maxn = 1000000;

LL gcd(LL a, LL b)
{
    return b==0?a:gcd(b, a%b);
}

int main()
{
    LL n;
    int kase = 0;
    while(scanf("%lld",&n) != EOF && n)
    {
        int ok = 0;
        printf("Scenario %d:
",++kase);
        for(LL i=1; i<=n && i<=maxn; i++)
        {
            if(n % i) continue;
            for(LL j=i+1; j<=i+25 && j<=maxn; j++)
            {
                if(n % j) continue;
                LL tem1 = i * j / gcd(i, j);
                for(LL k=j+1; k<=i+25 && k <= maxn; k++)
                {
                    if(n % k) continue;
                    LL tem2 = tem1 * k / gcd(tem1, k);
                    if(tem2 == n)
                    {
                        printf("%lld %lld %lld
",i,j,k);
                        ok = 1;
                    }
                }
            }
        }
        if(!ok) printf("Such bells don't exist
");

        printf("
");

    }

    return 0;
}
自己选择的路,跪着也要走完。朋友们,虽然这个世界日益浮躁起来,只要能够为了当时纯粹的梦想和感动坚持努力下去,不管其它人怎么样,我们也能够保持自己的本色走下去。
原文地址:https://www.cnblogs.com/WTSRUVF/p/9326977.html