java第六周作业

1.定义长度位5的整型数组,输入他们的值,用冒泡排序后输出.

package day01;
import java.util.*;
public class test3 {

public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input=new
Scanner (System.in);
int [] arr=new int [5];
System.out.println("input");
for (int i = 0; i < arr.length; i++) {
arr[i]=input.nextInt();
}
for (int i = 0; i < arr.length; i++) {
for (int j = 0; j < arr.length-i-1; j++) {
if(arr[j]>arr[j+1]){
int h=arr[j];
arr[j]=arr[j+1];
arr[j+1]=h;
}
}
}
for (int i = 0; i < arr.length; i++) {
System.out.println(arr[i]);
}
}

}

2.定义数组{34,22,35,67,45,66,12,33},输入一个数a,查找在数组中是否存在,如果存在,输出下标,不存在输出"not found"

import java.util.*;

public class test3 {
 
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner input=new
        Scanner (System.in);
        int [] arr={34,22,35,67,45,66,12,33};
        int x=0;
        System.out.print("input a=");
        int a=input.nextInt();
        for (int i = 0; i < arr.length; i++) {
            if(a==arr[i]){
                System.out.println("下标为"+i);
                x=1;
            }
             
        }
        if(x==0){
            System.out.println("no found");
        }
         
    }
 
}
3.以矩阵的形式输出一个double型二维数组(长度分别为5、4,值自己设定)的值。

package day01;

public class yeah {

public static void main(String[] args) {
// TODO Auto-generated method stub
double [][] f={{1,2,3,4,5},{6,7,8,9,10},{11,12,13,14,15},{16,17,18,19,20}};
for (int i = 0; i < 4; i++) {
for (int j = 0; j < 5; j++) {
System.out.print(f[i][j]);

}System.out.println();
}
}

}

4.定义一个二维数组(长度分别为3,4,值自己设定),求该二维数组的最大值.

package day01;

public class yeah {

public static void main(String[] args) {
// TODO Auto-generated method stub
int [][] ccc={{1,2,3,4},{6,7,8,9},{11,12,13,14}};
int max=0;
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 4; j++) {
if(ccc[i][j]>max)
max=ccc[i][j];

}
}
System.out.println("max="+max);
}

}

原文地址:https://www.cnblogs.com/WB9588/p/12703302.html