LeetCode 112 Path Sum

Problem:

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,

              5
             / 
            4   8
           /   / 
          11  13  4
         /        
        7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

Summary:

判断二叉树是否存在由根节点到某叶节点的路径权值等于sum。

Analysis:

前序遍历二叉树。

 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     bool hasPathSum(TreeNode* root, int sum) {
13         if (!root) return false;
14         if (root->left == NULL && root->right == NULL && root->val == sum)
15             return true;
16         return hasPathSum(root->left, sum - root->val) || hasPathSum(root->right, sum - root->val);
17     }
18 };