leetcode[81]Search in Rotated Sorted Array II

Follow up for "Search in Rotated Sorted Array":
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Write a function to determine if a given target is in the array.

class Solution {
public:
    bool search(int A[], int n, int target) {
        if(A==NULL||n==0)return false;
        int left=0, right=n-1;
        int mid;
        while(left<=right)
        {
            mid=(left+right)/2;
            if(A[mid]==target)return true;
            if (A[mid]==A[left]&&A[mid]==A[right])
            {
                left++;
                right--;
            }
            else if(A[mid]>=A[left])
            {
                if(A[mid]<target)left=mid+1;
                else
                {
                    if(target>=A[left])right=mid-1;
                    else left=mid+1;
                }
            }
            else
            {
                if(target<A[mid])right=mid-1;
                else 
                {
                    if (target<=A[right])left=mid+1;
                    else right=mid-1;
                }
            }
        }
        return false;
    }
};
原文地址:https://www.cnblogs.com/Vae1990Silence/p/4281445.html